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TRS Stand 20472 pair #381709969
details
property
value
status
complete
benchmark
12.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n050.star.cs.uiowa.edu
space
Der95
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.67765212059 seconds
cpu usage
3.62878045
max memory
1.93892352E8
stage attributes
key
value
output-size
1732
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 81 ms] (2) QTRS (3) RisEmptyProof [EQUIVALENT, 0 ms] (4) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: not(not(x)) -> x not(or(x, y)) -> and(not(x), not(y)) not(and(x, y)) -> or(not(x), not(y)) and(x, or(y, z)) -> or(and(x, y), and(x, z)) and(or(y, z), x) -> or(and(x, y), and(x, z)) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Quasi precedence: not_1 > and_2 > or_2 Status: not_1: multiset status or_2: multiset status and_2: multiset status With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: not(not(x)) -> x not(or(x, y)) -> and(not(x), not(y)) not(and(x, y)) -> or(not(x), not(y)) and(x, or(y, z)) -> or(and(x, y), and(x, z)) and(or(y, z), x) -> or(and(x, y), and(x, z)) ---------------------------------------- (2) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (3) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (4) YES
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