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TRS Stand 20472 pair #381710021
details
property
value
status
complete
benchmark
#3.56.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n081.star.cs.uiowa.edu
space
AG01
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.651170969009 seconds
cpu usage
1.406778848
max memory
2.3093248E8
stage attributes
key
value
output-size
2857
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: g(c(x,s(y))) -> g(c(s(x),y)) f(c(s(x),y)) -> f(c(x,s(y))) f(f(x)) -> f(d(f(x))) f(x) -> x Proof: Matrix Interpretation Processor: dim=1 interpretation: [d](x0) = x0, [f](x0) = 4x0 + 1, [g](x0) = 4x0, [c](x0, x1) = x0 + x1 + 3, [s](x0) = x0 + 1 orientation: g(c(x,s(y))) = 4x + 4y + 16 >= 4x + 4y + 16 = g(c(s(x),y)) f(c(s(x),y)) = 4x + 4y + 17 >= 4x + 4y + 17 = f(c(x,s(y))) f(f(x)) = 16x + 5 >= 16x + 5 = f(d(f(x))) f(x) = 4x + 1 >= x = x problem: g(c(x,s(y))) -> g(c(s(x),y)) f(c(s(x),y)) -> f(c(x,s(y))) f(f(x)) -> f(d(f(x))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [d](x0) = [0 0 0]x0 [0 0 0] , [1 0 1] [0] [f](x0) = [0 0 1]x0 + [0] [0 0 0] [1], [1 0 0] [0] [g](x0) = [0 1 0]x0 + [0] [0 0 0] [1], [1 0 0] [1 0 1] [c](x0, x1) = [0 0 0]x0 + [0 1 0]x1 [0 0 1] [0 0 0] , [1 0 0] [0] [s](x0) = [1 1 0]x0 + [0] [0 0 1] [1] orientation: [1 0 0] [1 0 1] [1] [1 0 0] [1 0 1] [0] g(c(x,s(y))) = [0 0 0]x + [1 1 0]y + [0] >= [0 0 0]x + [0 1 0]y + [0] = g(c(s(x),y)) [0 0 0] [0 0 0] [1] [0 0 0] [0 0 0] [1] [1 0 1] [1 0 1] [1] [1 0 1] [1 0 1] [1] f(c(s(x),y)) = [0 0 1]x + [0 0 0]y + [1] >= [0 0 1]x + [0 0 0]y + [0] = f(c(x,s(y))) [0 0 0] [0 0 0] [1] [0 0 0] [0 0 0] [1] [1 0 1] [1] [1 0 1] [0] f(f(x)) = [0 0 0]x + [1] >= [0 0 0]x + [0] = f(d(f(x))) [0 0 0] [1] [0 0 0] [1] problem: f(c(s(x),y)) -> f(c(x,s(y))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [f](x0) = [0 1 0]x0 [1 0 0] , [1 1 0] [1 0 0] [c](x0, x1) = [1 0 0]x0 + [0 0 0]x1 [0 0 1] [0 0 0] , [0] [s](x0) = x0 + [0] [1] orientation: [1 1 1] [1 0 0] [1] [1 1 1] [1 0 0] f(c(s(x),y)) = [1 0 0]x + [0 0 0]y + [0] >= [1 0 0]x + [0 0 0]y = f(c(x,s(y))) [1 1 0] [1 0 0] [0] [1 1 0] [1 0 0] problem: Qed
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