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TRS Stand 20472 pair #381710043
details
property
value
status
complete
benchmark
jones1.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n038.star.cs.uiowa.edu
space
Mixed_TRS
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.480741024017 seconds
cpu usage
0.723473145
max memory
1.09129728E8
stage attributes
key
value
output-size
3205
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: rev(ls) -> r1(ls,empty()) r1(empty(),a) -> a r1(cons(x,k),a) -> r1(k,cons(x,a)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [cons](x0, x1) = [0 0 1]x0 + x1 [0 0 0] , [1 0 1] [1 0 0] [r1](x0, x1) = [0 1 0]x0 + [0 1 1]x1 [0 0 0] [0 0 1] , [0] [empty] = [0] [1], [1 0 1] [0] [rev](x0) = [1 1 0]x0 + [1] [0 0 0] [1] orientation: [1 0 1] [0] [1 0 1] [0] rev(ls) = [1 1 0]ls + [1] >= [0 1 0]ls + [1] = r1(ls,empty()) [0 0 0] [1] [0 0 0] [1] [1 0 0] [1] r1(empty(),a) = [0 1 1]a + [0] >= a = a [0 0 1] [0] [1 0 0] [1 0 1] [1 0 1] [1 0 0] [1 0 1] [1 0 1] r1(cons(x,k),a) = [0 1 1]a + [0 1 0]k + [0 0 1]x >= [0 1 1]a + [0 1 0]k + [0 0 1]x = r1(k,cons(x,a)) [0 0 1] [0 0 0] [0 0 0] [0 0 1] [0 0 0] [0 0 0] problem: rev(ls) -> r1(ls,empty()) r1(cons(x,k),a) -> r1(k,cons(x,a)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [0] [cons](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 1] [1], [1 0 1] [1 0 0] [r1](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] , [0] [empty] = [0] [0], [1 0 1] [0] [rev](x0) = [0 0 0]x0 + [1] [0 0 0] [1] orientation: [1 0 1] [0] [1 0 1] rev(ls) = [0 0 0]ls + [1] >= [0 0 0]ls = r1(ls,empty()) [0 0 0] [1] [0 0 0] [1 0 0] [1 0 1] [1 0 0] [1] [1 0 0] [1 0 1] [1 0 0] r1(cons(x,k),a) = [0 0 0]a + [0 0 0]k + [0 0 0]x + [0] >= [0 0 0]a + [0 0 0]k + [0 0 0]x = r1(k,cons(x,a)) [0 0 0] [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] [0 0 0] problem: rev(ls) -> r1(ls,empty()) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [r1](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] , [0] [empty] = [0] [0], [1 0 0] [1] [rev](x0) = [0 0 0]x0 + [0] [0 0 0] [0] orientation: [1 0 0] [1] [1 0 0] rev(ls) = [0 0 0]ls + [0] >= [0 0 0]ls = r1(ls,empty()) [0 0 0] [0] [0 0 0] problem: Qed
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