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TRS Stand 20472 pair #381710545
details
property
value
status
complete
benchmark
02.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n028.star.cs.uiowa.edu
space
Der95
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.423872947693 seconds
cpu usage
0.564475379
max memory
1.1493376E8
stage attributes
key
value
output-size
865
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: .(1(),x) -> x .(x,1()) -> x .(i(x),x) -> 1() .(x,i(x)) -> 1() i(1()) -> 1() i(i(x)) -> x .(i(y),.(y,z)) -> z .(y,.(i(y),z)) -> z Proof: Matrix Interpretation Processor: dim=1 interpretation: [i](x0) = x0 + 4, [.](x0, x1) = x0 + x1 + 7, [1] = 0 orientation: .(1(),x) = x + 7 >= x = x .(x,1()) = x + 7 >= x = x .(i(x),x) = 2x + 11 >= 0 = 1() .(x,i(x)) = 2x + 11 >= 0 = 1() i(1()) = 4 >= 0 = 1() i(i(x)) = x + 8 >= x = x .(i(y),.(y,z)) = 2y + z + 18 >= z = z .(y,.(i(y),z)) = 2y + z + 18 >= z = z problem: Qed
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