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TRS Stand 20472 pair #381710583
details
property
value
status
complete
benchmark
nrvsq.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n105.star.cs.uiowa.edu
space
MNZ_10
run statistics
property
value
solver
Wanda
configuration
FirstOrder
runtime (wallclock)
2.09964799881 seconds
cpu usage
2.096183312
max memory
6.3270912E7
stage attributes
key
value
output-size
1133
starexec-result
MAYBE
output
/export/starexec/sandbox2/solver/bin/starexec_run_FirstOrder /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE We consider the system theBenchmark. We are asked to determine termination of the following first-order TRS. 0 : [] --> o a : [] --> o f : [o] --> o g : [o] --> o h : [o * o] --> o k : [o] --> o p : [o] --> o r : [o] --> o s : [o] --> o f(g(X)) => g(g(f(X))) g(s(X)) => s(s(g(X))) s(X) => h(0, X) s(X) => h(X, 0) f(0) => 0 s(s(s(0))) => f(s(0)) f(s(0)) => s(0) h(f(X), g(X)) => f(s(X)) g(X) => h(h(h(h(X, X), X), X), X) f(s(s(X))) => h(f(X), g(h(X, X))) s(0) => r(0) s(s(s(0))) => r(s(0)) r(s(0)) => s(0) g(X) => r(X) s(0) => p(0) s(s(0)) => p(s(0)) p(s(0)) => 0 s(s(s(s(s(0))))) => p(s(s(0))) p(s(s(0))) => s(s(s(0))) h(p(X), g(X)) => p(s(X)) s(0) => k(0) s(s(p(p(a)))) => s(k(p(a))) s(k(p(a))) => p(p(a)) g(X) => k(X) a => 0 s(h(r(k(p(X))), r(X))) => h(r(r(p(X))), k(X))
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