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TRS Stand 20472 pair #381710985
details
property
value
status
complete
benchmark
ex01.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n056.star.cs.uiowa.edu
space
Zantema_15
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.20200204849 seconds
cpu usage
5.803278012
max memory
6.2019584E8
stage attributes
key
value
output-size
1506
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 242 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(L(x)) -> L(a(x)) R(a(x)) -> a(R(x)) b(L(x)) -> b(R(x)) R(b(x)) -> L(a(b(x))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "b R (a)^k b -> b R (a)^k+1 b" b R (a)^k b -> b R (a)^k+1 b by Overlap u with l (ol4)"R (a)^k b -> L (a)^k+1 b by Equivalent"R (a)^k b -> L (a)^k a b by Overlapping Derivationstructures"R (a)^k b -> (a)^k L a b by Overlap u with r (ol3)"R (a)^k -> (a)^k R by Selfoverlapping OC am2"R a -> a R by original rule (OC 1)"""R b -> L a b by original rule (OC 1)"""(a)^k L -> L (a)^k by Selfoverlapping OC am1"a L -> L a by original rule (OC 1)"""""b L -> b R by original rule (OC 1)" ---------------------------------------- (2) NO
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