details

property	value
status	complete
benchmark	IJCAR_26.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n083.star.cs.uiowa.edu
space	AProVE_04

run statistics

property	value
solver	Wanda
configuration	FirstOrder
runtime (wallclock)	0.572122097015 seconds
cpu usage	0.569692664
max memory	2.9130752E7

stage attributes

key	value
output-size	1439
starexec-result	MAYBE

output

/export/starexec/sandbox2/solver/bin/starexec_run_FirstOrder /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE We consider the system theBenchmark. We are asked to determine termination of the following first-order TRS. 0 : [] --> o div : [o * o] --> o divides : [o * o] --> o eq : [o * o] --> o false : [] --> o if : [o * o * o] --> o p : [o] --> o plus : [o * o] --> o pr : [o * o] --> o prime : [o] --> o quot : [o * o * o] --> o s : [o] --> o times : [o * o] --> o true : [] --> o p(s(X)) => X plus(X, 0) => X plus(0, X) => X plus(s(X), Y) => s(plus(X, Y)) plus(s(X), Y) => s(plus(p(s(X)), Y)) plus(X, s(Y)) => s(plus(X, p(s(Y)))) times(0, X) => 0 times(s(0), X) => X times(s(X), Y) => plus(Y, times(X, Y)) div(0, X) => 0 div(X, Y) => quot(X, Y, Y) quot(0, s(X), Y) => 0 quot(s(X), s(Y), Z) => quot(X, Y, Z) quot(X, 0, s(Y)) => s(div(X, s(Y))) div(div(X, Y), Z) => div(X, times(Y, Z)) eq(0, 0) => true eq(s(X), 0) => false eq(0, s(X)) => false eq(s(X), s(Y)) => eq(X, Y) divides(X, Y) => eq(Y, times(div(Y, X), X)) prime(s(s(X))) => pr(s(s(X)), s(X)) pr(X, s(0)) => true pr(X, s(s(Y))) => if(divides(s(s(Y)), X), X, s(Y)) if(true, X, Y) => false if(false, X, Y) => pr(X, Y) popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Stand 20472