details

property	value
status	complete
benchmark	pair3swap.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n082.star.cs.uiowa.edu
space	Endrullis_06

run statistics

property	value
solver	ttt2-1.17+nonreach
configuration	ttt2-1.17+nonreach
runtime (wallclock)	2.98522591591 seconds
cpu usage	10.393337044
max memory	8.55670784E8

stage attributes

key	value
output-size	2650
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: p(a(a(x0)),p(x1,p(a(x2),x3))) -> p(x2,p(a(a(b(x1))),p(a(a(x0)),x3))) Proof: DP Processor: DPs: p#(a(a(x0)),p(x1,p(a(x2),x3))) -> p#(a(a(x0)),x3) p#(a(a(x0)),p(x1,p(a(x2),x3))) -> p#(a(a(b(x1))),p(a(a(x0)),x3)) p#(a(a(x0)),p(x1,p(a(x2),x3))) -> p#(x2,p(a(a(b(x1))),p(a(a(x0)),x3))) TRS: p(a(a(x0)),p(x1,p(a(x2),x3))) -> p(x2,p(a(a(b(x1))),p(a(a(x0)),x3))) Subterm Criterion Processor: simple projection: pi(p) = [1,1] pi(p#) = [1,1] problem: DPs: p#(a(a(x0)),p(x1,p(a(x2),x3))) -> p#(x2,p(a(a(b(x1))),p(a(a(x0)),x3))) TRS: p(a(a(x0)),p(x1,p(a(x2),x3))) -> p(x2,p(a(a(b(x1))),p(a(a(x0)),x3))) Matrix Interpretation Processor: dim=4 usable rules: p(a(a(x0)),p(x1,p(a(x2),x3))) -> p(x2,p(a(a(b(x1))),p(a(a(x0)),x3))) interpretation: [p#](x0, x1) = [1 1 1 0]x0 + [0 1 0 0]x1 + [1], [1 0 0 0] [0 0 0 0] [b](x0) = [0 0 0 0]x0 [0 0 0 0] , [1 0 1 0] [0 0 0 1] [1 0 1 0] [0 0 0 1] [p](x0, x1) = [0 0 0 0]x0 + [0 0 0 0]x1 [1 0 1 0] [0 0 0 1] , [0 1 0 0] [0] [0 0 0 1] [0] [a](x0) = [1 1 1 0]x0 + [0] [0 0 0 0] [1] orientation: p#(a(a(x0)),p(x1,p(a(x2),x3))) = [1 2 1 2]x0 + [1 0 1 0]x1 + [1 2 1 0]x2 + [0 0 0 1]x3 + [2] >= [1 2 1 2]x0 + [1 0 0 0]x1 + [1 1 1 0]x2 + [0 0 0 1]x3 + [1] = p#(x2,p(a(a(b(x1))),p(a(a(x0)),x3))) [1 2 1 2] [1 0 1 0] [1 2 1 0] [0 0 0 1] [1 2 1 2] [1 0 0 0] [1 0 1 0] [0 0 0 1] [1 2 1 2] [1 0 1 0] [1 2 1 0] [0 0 0 1] [1 2 1 2] [1 0 0 0] [1 0 1 0] [0 0 0 1] p(a(a(x0)),p(x1,p(a(x2),x3))) = [0 0 0 0]x0 + [0 0 0 0]x1 + [0 0 0 0]x2 + [0 0 0 0]x3 >= [0 0 0 0]x0 + [0 0 0 0]x1 + [0 0 0 0]x2 + [0 0 0 0]x3 = p(x2,p(a(a(b(x1))),p(a(a(x0)),x3))) [1 2 1 2] [1 0 1 0] [1 2 1 0] [0 0 0 1] [1 2 1 2] [1 0 0 0] [1 0 1 0] [0 0 0 1] problem: DPs: TRS: p(a(a(x0)),p(x1,p(a(x2),x3))) -> p(x2,p(a(a(b(x1))),p(a(a(x0)),x3))) Qed popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Stand 20472