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TRS Stand 20472 pair #381711521
details
property
value
status
complete
benchmark
quadruple1.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n089.star.cs.uiowa.edu
space
Endrullis_06
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.957543134689 seconds
cpu usage
2.45175405
max memory
2.46222848E8
stage attributes
key
value
output-size
1972
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(x3,a(x2)),p(b(a(x1)),b(x0))) Proof: DP Processor: DPs: p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(b(a(x1)),b(x0)) p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,a(x2)) p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(x3,a(x2)),p(b(a(x1)),b(x0))) TRS: p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(x3,a(x2)),p(b(a(x1)),b(x0))) EDG Processor: DPs: p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(b(a(x1)),b(x0)) p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,a(x2)) p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(x3,a(x2)),p(b(a(x1)),b(x0))) TRS: p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(x3,a(x2)),p(b(a(x1)),b(x0))) graph: p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(x3,a(x2)),p(b(a(x1)),b(x0))) -> p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(b(a(x1)),b(x0)) p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(x3,a(x2)),p(b(a(x1)),b(x0))) -> p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,a(x2)) p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(x3,a(x2)),p(b(a(x1)),b(x0))) -> p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(x3,a(x2)),p(b(a(x1)),b(x0))) SCC Processor: #sccs: 1 #rules: 1 #arcs: 3/9 DPs: p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(x3,a(x2)),p(b(a(x1)),b(x0))) TRS: p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(x3,a(x2)),p(b(a(x1)),b(x0))) Bounds Processor: bound: 0 enrichment: match automaton: final states: {9,1} transitions: f40() -> 2* p{#,0}(8,6) -> 1* p0(3,15) -> 8* p0(5,3) -> 6* p0(2,7) -> 8* p0(8,6) -> 9* a0(15) -> 4* a0(5) -> 15* a0(7) -> 4* a0(2) -> 7,4 b0(2) -> 3* b0(4) -> 5* problem: DPs: TRS: p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(x3,a(x2)),p(b(a(x1)),b(x0))) Qed
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