Spaces
Explore
Communities
Statistics
Reports
Cluster
Status
Help
TRS Stand 20472 pair #381711788
details
property
value
status
complete
benchmark
z19.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n095.star.cs.uiowa.edu
space
Zantema_05
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
15.6444959641 seconds
cpu usage
34.877178624
max memory
4.360671232E9
stage attributes
key
value
output-size
19733
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) MRRProof [EQUIVALENT, 0 ms] (4) QDP (5) SemLabProof [SOUND, 183 ms] (6) QDP (7) DependencyGraphProof [EQUIVALENT, 0 ms] (8) QDP (9) QDPOrderProof [EQUIVALENT, 9 ms] (10) QDP (11) QDPOrderProof [EQUIVALENT, 1 ms] (12) QDP (13) DependencyGraphProof [EQUIVALENT, 0 ms] (14) AND (15) QDP (16) QDPOrderProof [EQUIVALENT, 0 ms] (17) QDP (18) QDPOrderProof [EQUIVALENT, 0 ms] (19) QDP (20) UsableRulesReductionPairsProof [EQUIVALENT, 0 ms] (21) QDP (22) PisEmptyProof [EQUIVALENT, 0 ms] (23) YES (24) QDP (25) UsableRulesReductionPairsProof [EQUIVALENT, 0 ms] (26) QDP (27) PisEmptyProof [EQUIVALENT, 0 ms] (28) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(f(a, a), x) -> f(a, f(b, f(a, x))) f(x, f(y, z)) -> f(f(x, y), z) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: F(f(a, a), x) -> F(a, f(b, f(a, x))) F(f(a, a), x) -> F(b, f(a, x)) F(f(a, a), x) -> F(a, x) F(x, f(y, z)) -> F(f(x, y), z) F(x, f(y, z)) -> F(x, y) The TRS R consists of the following rules: f(f(a, a), x) -> f(a, f(b, f(a, x))) f(x, f(y, z)) -> f(f(x, y), z) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) MRRProof (EQUIVALENT) By using the rule removal processor [LPAR04] with the following ordering, at least one Dependency Pair or term rewrite system rule of this QDP problem can be strictly oriented. Strictly oriented dependency pairs: F(f(a, a), x) -> F(b, f(a, x)) F(f(a, a), x) -> F(a, x) Used ordering: Polynomial interpretation [POLO]: POL(F(x_1, x_2)) = 2*x_1 + 2*x_2 POL(a) = 2 POL(b) = 0 POL(f(x_1, x_2)) = x_1 + x_2 ----------------------------------------
popout
output may be truncated. 'popout' for the full output.
job log
popout
actions
all output
return to TRS Stand 20472