Spaces
Explore
Communities
Statistics
Reports
Cluster
Status
Help
TRS Stand 20472 pair #381711846
details
property
value
status
complete
benchmark
19.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n006.star.cs.uiowa.edu
space
Various_04
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.659013986588 seconds
cpu usage
1.447837392
max memory
1.7975296E8
stage attributes
key
value
output-size
1902
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: :(x,x) -> e() :(x,e()) -> x i(:(x,y)) -> :(y,x) :(:(x,y),z) -> :(x,:(z,i(y))) :(e(),x) -> i(x) i(i(x)) -> x i(e()) -> e() :(x,:(y,i(x))) -> i(y) :(x,:(y,:(i(x),z))) -> :(i(z),y) :(i(x),:(y,x)) -> i(y) :(i(x),:(y,:(x,z))) -> :(i(z),y) Proof: Matrix Interpretation Processor: dim=1 interpretation: [i](x0) = x0, [e] = 4, [:](x0, x1) = x0 + x1 + 4 orientation: :(x,x) = 2x + 4 >= 4 = e() :(x,e()) = x + 8 >= x = x i(:(x,y)) = x + y + 4 >= x + y + 4 = :(y,x) :(:(x,y),z) = x + y + z + 8 >= x + y + z + 8 = :(x,:(z,i(y))) :(e(),x) = x + 8 >= x = i(x) i(i(x)) = x >= x = x i(e()) = 4 >= 4 = e() :(x,:(y,i(x))) = 2x + y + 8 >= y = i(y) :(x,:(y,:(i(x),z))) = 2x + y + z + 12 >= y + z + 4 = :(i(z),y) :(i(x),:(y,x)) = 2x + y + 8 >= y = i(y) :(i(x),:(y,:(x,z))) = 2x + y + z + 12 >= y + z + 4 = :(i(z),y) problem: :(x,x) -> e() i(:(x,y)) -> :(y,x) :(:(x,y),z) -> :(x,:(z,i(y))) i(i(x)) -> x i(e()) -> e() Matrix Interpretation Processor: dim=1 interpretation: [i](x0) = x0, [e] = 0, [:](x0, x1) = x0 + x1 + 2 orientation: :(x,x) = 2x + 2 >= 0 = e() i(:(x,y)) = x + y + 2 >= x + y + 2 = :(y,x) :(:(x,y),z) = x + y + z + 4 >= x + y + z + 4 = :(x,:(z,i(y))) i(i(x)) = x >= x = x i(e()) = 0 >= 0 = e() problem: i(:(x,y)) -> :(y,x) :(:(x,y),z) -> :(x,:(z,i(y))) i(i(x)) -> x i(e()) -> e() KBO Processor: weight function: w0 = 1 w(e) = 1 w(i) = w(:) = 0 precedence: i > e ~ : problem: Qed
popout
output may be truncated. 'popout' for the full output.
job log
popout
actions
all output
return to TRS Stand 20472