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TRS Stand 20472 pair #381711899
details
property
value
status
complete
benchmark
gen-17.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n096.star.cs.uiowa.edu
space
Secret_06_TRS
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.178208827972 seconds
cpu usage
0.150318089
max memory
7376896.0
stage attributes
key
value
output-size
2072
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y z) (RULES c(b(a,a),b(y,z),x) -> b(a,b(z,z)) f(c(c(a,y,a),b(x,z),a)) -> b(y,f(c(f(a),z,z))) f(b(b(x,f(y)),z)) -> c(z,x,f(b(b(f(a),y),y))) ) Problem 1: Dependency Pairs Processor: -> Pairs: F(b(b(x,f(y)),z)) -> C(z,x,f(b(b(f(a),y),y))) F(b(b(x,f(y)),z)) -> F(b(b(f(a),y),y)) -> Rules: c(b(a,a),b(y,z),x) -> b(a,b(z,z)) f(c(c(a,y,a),b(x,z),a)) -> b(y,f(c(f(a),z,z))) f(b(b(x,f(y)),z)) -> c(z,x,f(b(b(f(a),y),y))) Problem 1: SCC Processor: -> Pairs: F(b(b(x,f(y)),z)) -> C(z,x,f(b(b(f(a),y),y))) F(b(b(x,f(y)),z)) -> F(b(b(f(a),y),y)) -> Rules: c(b(a,a),b(y,z),x) -> b(a,b(z,z)) f(c(c(a,y,a),b(x,z),a)) -> b(y,f(c(f(a),z,z))) f(b(b(x,f(y)),z)) -> c(z,x,f(b(b(f(a),y),y))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: F(b(b(x,f(y)),z)) -> F(b(b(f(a),y),y)) ->->-> Rules: c(b(a,a),b(y,z),x) -> b(a,b(z,z)) f(c(c(a,y,a),b(x,z),a)) -> b(y,f(c(f(a),z,z))) f(b(b(x,f(y)),z)) -> c(z,x,f(b(b(f(a),y),y))) Problem 1: Reduction Pair Processor: -> Pairs: F(b(b(x,f(y)),z)) -> F(b(b(f(a),y),y)) -> Rules: c(b(a,a),b(y,z),x) -> b(a,b(z,z)) f(c(c(a,y,a),b(x,z),a)) -> b(y,f(c(f(a),z,z))) f(b(b(x,f(y)),z)) -> c(z,x,f(b(b(f(a),y),y))) -> Usable rules: c(b(a,a),b(y,z),x) -> b(a,b(z,z)) f(c(c(a,y,a),b(x,z),a)) -> b(y,f(c(f(a),z,z))) f(b(b(x,f(y)),z)) -> c(z,x,f(b(b(f(a),y),y))) ->Interpretation type: Linear ->Coefficients: All rationals ->Dimension: 1 ->Bound: 4 ->Interpretation: [c](X1,X2,X3) = 2/3.X1 + 3.X2 + 3/2 [f](X) = 3.X + 1 [a] = 0 [b](X1,X2) = X1 + 4/3.X2 + 4 [F](X) = 4/3.X Problem 1: SCC Processor: -> Pairs: Empty -> Rules: c(b(a,a),b(y,z),x) -> b(a,b(z,z)) f(c(c(a,y,a),b(x,z),a)) -> b(y,f(c(f(a),z,z))) f(b(b(x,f(y)),z)) -> c(z,x,f(b(b(f(a),y),y))) ->Strongly Connected Components: There is no strongly connected component The problem is finite.
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