details

property	value
status	complete
benchmark	lepper_1.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n013.star.cs.uiowa.edu
space	Hydras

run statistics

property	value
solver	Wanda
configuration	FirstOrder
runtime (wallclock)	1.04178404808 seconds
cpu usage	1.038354081
max memory	6.0592128E7

stage attributes

key	value
output-size	1606
starexec-result	MAYBE

output

/export/starexec/sandbox2/solver/bin/starexec_run_FirstOrder /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE We consider the system theBenchmark. We are asked to determine termination of the following first-order TRS. !plus : [o * o] --> o 0 : [] --> o J1 : [o * o] --> o M : [o * o] --> o P : [o * o] --> o Q11 : [o * o] --> o R1 : [o * o * o] --> o S : [o] --> o a : [o] --> o l : [o] --> o o : [o] --> o a(X) => X o(X) => X l(X) => X S(X) => X !plus(X, Y) => Y !plus(X, Y) => X P(X, Y) => Y P(X, Y) => X M(X, Y) => Y M(X, Y) => X J1(X, Y) => Y J1(X, Y) => X Q11(X, Y) => Y Q11(X, Y) => X R1(X, Y, Z) => Z R1(X, Y, Z) => Y R1(X, Y, Z) => X P(0, 0) => S(0) !plus(X, S(Y)) => S(!plus(X, Y)) a(l(X)) => l(a(a(X))) l(o(X)) => o(l(l(X))) o(X) => l(X) l(X) => a(X) a(S(X)) => S(l(X)) a(!plus(X, Y)) => !plus(l(X), Y) a(!plus(X, Y)) => !plus(X, l(Y)) a(P(X, Y)) => P(X, l(Y)) a(P(X, Y)) => P(l(X), Y) !plus(X, o(Y)) => o(!plus(X, Y)) P(X, o(Y)) => o(P(X, Y)) P(o(X), Y) => o(P(X, Y)) M(X, l(Y)) => !plus(M(X, Y), P(X, Y)) J1(l(X), Y) => P(J1(X, Y), 0) a(S(X)) => o(X) P(0, S(X)) => o(M(0, X)) P(0, P(X, Y)) => o(M(X, Y)) P(S(X), Y) => o(J1(X, Y)) P(S(X), S(Y)) => o(J1(X, P(S(X), Y))) a(P(X, 0)) => Q11(a(X), X) Q11(o(X), Y) => o(P(X, Y)) a(P(X, S(Y))) => R1(a(X), X, Y) R1(o(X), Y, Z) => o(P(X, P(Y, Z))) popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to TRS Stand 20472