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TRS Stand 20472 pair #381712323
details
property
value
status
complete
benchmark
aprove5.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n009.star.cs.uiowa.edu
space
Secret_05_TRS
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.21188402176 seconds
cpu usage
5.454975097
max memory
2.96665088E8
stage attributes
key
value
output-size
22226
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) AND (5) QDP (6) UsableRulesProof [EQUIVALENT, 0 ms] (7) QDP (8) QDPSizeChangeProof [EQUIVALENT, 0 ms] (9) YES (10) QDP (11) UsableRulesProof [EQUIVALENT, 0 ms] (12) QDP (13) MNOCProof [EQUIVALENT, 0 ms] (14) QDP (15) DependencyGraphProof [EQUIVALENT, 0 ms] (16) AND (17) QDP (18) UsableRulesProof [EQUIVALENT, 0 ms] (19) QDP (20) QReductionProof [EQUIVALENT, 0 ms] (21) QDP (22) QDPOrderProof [EQUIVALENT, 22 ms] (23) QDP (24) PisEmptyProof [EQUIVALENT, 0 ms] (25) YES (26) QDP (27) QDPSizeChangeProof [EQUIVALENT, 0 ms] (28) YES (29) QDP (30) UsableRulesProof [EQUIVALENT, 0 ms] (31) QDP (32) MNOCProof [EQUIVALENT, 0 ms] (33) QDP (34) UsableRulesReductionPairsProof [EQUIVALENT, 16 ms] (35) QDP (36) TransformationProof [EQUIVALENT, 0 ms] (37) QDP (38) UsableRulesProof [EQUIVALENT, 0 ms] (39) QDP (40) QDPOrderProof [EQUIVALENT, 15 ms] (41) QDP (42) PisEmptyProof [EQUIVALENT, 0 ms] (43) YES (44) QDP (45) QDPOrderProof [EQUIVALENT, 0 ms] (46) QDP (47) QDPOrderProof [EQUIVALENT, 0 ms] (48) QDP (49) PisEmptyProof [EQUIVALENT, 0 ms] (50) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: minus(x, 0) -> x minus(0, y) -> 0 minus(s(x), s(y)) -> minus(p(s(x)), p(s(y))) minus(x, plus(y, z)) -> minus(minus(x, y), z) p(s(s(x))) -> s(p(s(x))) p(0) -> s(s(0)) div(s(x), s(y)) -> s(div(minus(x, y), s(y))) div(plus(x, y), z) -> plus(div(x, z), div(y, z)) plus(0, y) -> y plus(s(x), y) -> s(plus(y, minus(s(x), s(0)))) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: MINUS(s(x), s(y)) -> MINUS(p(s(x)), p(s(y))) MINUS(s(x), s(y)) -> P(s(x)) MINUS(s(x), s(y)) -> P(s(y))
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