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TRS Stand 20472 pair #381712480
details
property
value
status
complete
benchmark
Liveness6.2.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n042.star.cs.uiowa.edu
space
AProVE_04
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.594674825668 seconds
cpu usage
1.116188984
max memory
1.55365376E8
stage attributes
key
value
output-size
4354
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: top(sent(x)) -> top(check(rest(x))) rest(nil()) -> sent(nil()) rest(cons(x,y)) -> sent(y) check(sent(x)) -> sent(check(x)) check(rest(x)) -> rest(check(x)) check(cons(x,y)) -> cons(check(x),y) check(cons(x,y)) -> cons(x,check(y)) check(cons(x,y)) -> cons(x,y) Proof: Matrix Interpretation Processor: dim=1 interpretation: [cons](x0, x1) = x0 + 4x1 + 5, [nil] = 0, [check](x0) = 2x0, [rest](x0) = x0, [top](x0) = x0, [sent](x0) = 4x0 orientation: top(sent(x)) = 4x >= 2x = top(check(rest(x))) rest(nil()) = 0 >= 0 = sent(nil()) rest(cons(x,y)) = x + 4y + 5 >= 4y = sent(y) check(sent(x)) = 8x >= 8x = sent(check(x)) check(rest(x)) = 2x >= 2x = rest(check(x)) check(cons(x,y)) = 2x + 8y + 10 >= 2x + 4y + 5 = cons(check(x),y) check(cons(x,y)) = 2x + 8y + 10 >= x + 8y + 5 = cons(x,check(y)) check(cons(x,y)) = 2x + 8y + 10 >= x + 4y + 5 = cons(x,y) problem: top(sent(x)) -> top(check(rest(x))) rest(nil()) -> sent(nil()) check(sent(x)) -> sent(check(x)) check(rest(x)) -> rest(check(x)) Matrix Interpretation Processor: dim=3 interpretation: [0] [nil] = [1] [1], [1 0 0] [check](x0) = [0 0 0]x0 [0 0 0] , [1 1 0] [rest](x0) = [0 1 0]x0 [0 1 0] , [1 0 1] [0] [top](x0) = [0 1 0]x0 + [1] [0 0 1] [0], [1 0 0] [sent](x0) = [0 0 1]x0 [0 1 0] orientation: [1 1 0] [0] [1 1 0] [0] top(sent(x)) = [0 0 1]x + [1] >= [0 0 0]x + [1] = top(check(rest(x))) [0 1 0] [0] [0 0 0] [0] [1] [0] rest(nil()) = [1] >= [1] = sent(nil()) [1] [1] [1 0 0] [1 0 0] check(sent(x)) = [0 0 0]x >= [0 0 0]x = sent(check(x)) [0 0 0] [0 0 0] [1 1 0] [1 0 0] check(rest(x)) = [0 0 0]x >= [0 0 0]x = rest(check(x)) [0 0 0] [0 0 0] problem: top(sent(x)) -> top(check(rest(x))) check(sent(x)) -> sent(check(x)) check(rest(x)) -> rest(check(x)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1]
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