Spaces
Explore
Communities
Statistics
Reports
Cluster
Status
Help
TRS Stand 20472 pair #381712612
details
property
value
status
complete
benchmark
24.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n025.star.cs.uiowa.edu
space
Various_04
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.841839075089 seconds
cpu usage
2.124918214
max memory
2.793472E8
stage attributes
key
value
output-size
3890
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: max(L(x)) -> x max(N(L(0()),L(y))) -> y max(N(L(s(x)),L(s(y)))) -> s(max(N(L(x),L(y)))) max(N(L(x),N(y,z))) -> max(N(L(x),L(max(N(y,z))))) Proof: Matrix Interpretation Processor: dim=1 interpretation: [s](x0) = 2x0 + 5, [N](x0, x1) = x0 + 4x1, [0] = 0, [max](x0) = x0, [L](x0) = x0 orientation: max(L(x)) = x >= x = x max(N(L(0()),L(y))) = 4y >= y = y max(N(L(s(x)),L(s(y)))) = 2x + 8y + 25 >= 2x + 8y + 5 = s(max(N(L(x),L(y)))) max(N(L(x),N(y,z))) = x + 4y + 16z >= x + 4y + 16z = max(N(L(x),L(max(N(y,z))))) problem: max(L(x)) -> x max(N(L(0()),L(y))) -> y max(N(L(x),N(y,z))) -> max(N(L(x),L(max(N(y,z))))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [N](x0, x1) = [0 1 0]x0 + x1 [0 0 0] , [1] [0] = [0] [0], [1 0 0] [max](x0) = [0 0 1]x0 [0 1 0] , [1 0 0] [L](x0) = [0 0 1]x0 [0 1 0] orientation: max(L(x)) = x >= x = x [1] max(N(L(0()),L(y))) = y + [0] >= y = y [0] [1 0 0] [1 0 0] [1 0 0] [1 0 0] [1 0 0] [1 0 0] max(N(L(x),N(y,z))) = [0 0 0]x + [0 0 0]y + [0 0 1]z >= [0 0 0]x + [0 0 0]y + [0 0 1]z = max(N(L(x),L(max(N(y,z))))) [0 0 1] [0 1 0] [0 1 0] [0 0 1] [0 1 0] [0 1 0] problem: max(L(x)) -> x max(N(L(x),N(y,z))) -> max(N(L(x),L(max(N(y,z))))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 1 1] [0] [N](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [1] [0 0 0] [0 0 0] [0], [1 0 1] [max](x0) = [0 0 1]x0 [0 0 1] , [1 0 0] [0] [L](x0) = [0 0 0]x0 + [0] [0 1 1] [1] orientation: [1 1 1] [1] max(L(x)) = [0 1 1]x + [1] >= x = x [0 1 1] [1] [1 0 0] [1 0 0] [1 1 1] [1] [1 0 0] [1 0 0] [1 1 1] [1] max(N(L(x),N(y,z))) = [0 0 0]x + [0 0 0]y + [0 0 0]z + [0] >= [0 0 0]x + [0 0 0]y + [0 0 0]z + [0] = max(N(L(x),L(max(N(y,z))))) [0 0 0] [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] [0 0 0] [0] problem: max(N(L(x),N(y,z))) -> max(N(L(x),L(max(N(y,z))))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 1] [0]
popout
output may be truncated. 'popout' for the full output.
job log
popout
actions
all output
return to TRS Stand 20472