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TRS Stand 20472 pair #381712628
details
property
value
status
complete
benchmark
times.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n093.star.cs.uiowa.edu
space
Secret_06_TRS
run statistics
property
value
solver
Wanda
configuration
FirstOrder
runtime (wallclock)
0.698981046677 seconds
cpu usage
0.693644778
max memory
3.2985088E7
stage attributes
key
value
output-size
1314
starexec-result
MAYBE
output
/export/starexec/sandbox2/solver/bin/starexec_run_FirstOrder /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE We consider the system theBenchmark. We are asked to determine termination of the following first-order TRS. 0 : [] --> o eq : [o * o] --> o f : [] --> o false : [] --> o g : [] --> o h : [] --> o ifPlus : [o * o * o * o] --> o ifTimes : [o * o * o * o * o] --> o inc : [o] --> o minus : [o * o] --> o plus : [o * o] --> o s : [o] --> o times : [o * o] --> o timesIter : [o * o * o] --> o true : [] --> o inc(s(X)) => s(inc(X)) inc(0) => s(0) plus(X, Y) => ifPlus(eq(X, 0), minus(X, s(0)), X, inc(X)) ifPlus(false, X, Y, Z) => plus(X, Z) ifPlus(true, X, Y, Z) => Y minus(s(X), s(Y)) => minus(X, Y) minus(0, X) => 0 minus(X, 0) => X minus(X, X) => 0 eq(s(X), s(Y)) => eq(X, Y) eq(0, s(X)) => false eq(s(X), 0) => false eq(0, 0) => true eq(X, X) => true times(X, Y) => timesIter(X, Y, 0) timesIter(X, Y, Z) => ifTimes(eq(X, 0), minus(X, s(0)), Y, Z, plus(Y, Z)) ifTimes(true, X, Y, Z, U) => Z ifTimes(false, X, Y, Z, U) => timesIter(X, Y, U) f => g f => h
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