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TRS Stand 20472 pair #381712658
details
property
value
status
complete
benchmark
24.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n033.star.cs.uiowa.edu
space
Various_04
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.0401258468628 seconds
cpu usage
0.029577936
max memory
3309568.0
stage attributes
key
value
output-size
3248
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y z) (RULES max(L(x)) -> x max(N(L(0),L(y))) -> y max(N(L(s(x)),L(s(y)))) -> s(max(N(L(x),L(y)))) max(N(L(x),N(y,z))) -> max(N(L(x),L(max(N(y,z))))) ) Problem 1: Innermost Equivalent Processor: -> Rules: max(L(x)) -> x max(N(L(0),L(y))) -> y max(N(L(s(x)),L(s(y)))) -> s(max(N(L(x),L(y)))) max(N(L(x),N(y,z))) -> max(N(L(x),L(max(N(y,z))))) -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: MAX(N(L(s(x)),L(s(y)))) -> MAX(N(L(x),L(y))) MAX(N(L(x),N(y,z))) -> MAX(N(L(x),L(max(N(y,z))))) MAX(N(L(x),N(y,z))) -> MAX(N(y,z)) -> Rules: max(L(x)) -> x max(N(L(0),L(y))) -> y max(N(L(s(x)),L(s(y)))) -> s(max(N(L(x),L(y)))) max(N(L(x),N(y,z))) -> max(N(L(x),L(max(N(y,z))))) Problem 1: SCC Processor: -> Pairs: MAX(N(L(s(x)),L(s(y)))) -> MAX(N(L(x),L(y))) MAX(N(L(x),N(y,z))) -> MAX(N(L(x),L(max(N(y,z))))) MAX(N(L(x),N(y,z))) -> MAX(N(y,z)) -> Rules: max(L(x)) -> x max(N(L(0),L(y))) -> y max(N(L(s(x)),L(s(y)))) -> s(max(N(L(x),L(y)))) max(N(L(x),N(y,z))) -> max(N(L(x),L(max(N(y,z))))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: MAX(N(L(s(x)),L(s(y)))) -> MAX(N(L(x),L(y))) ->->-> Rules: max(L(x)) -> x max(N(L(0),L(y))) -> y max(N(L(s(x)),L(s(y)))) -> s(max(N(L(x),L(y)))) max(N(L(x),N(y,z))) -> max(N(L(x),L(max(N(y,z))))) ->->Cycle: ->->-> Pairs: MAX(N(L(x),N(y,z))) -> MAX(N(y,z)) ->->-> Rules: max(L(x)) -> x max(N(L(0),L(y))) -> y max(N(L(s(x)),L(s(y)))) -> s(max(N(L(x),L(y)))) max(N(L(x),N(y,z))) -> max(N(L(x),L(max(N(y,z))))) The problem is decomposed in 2 subproblems. Problem 1.1: Reduction Pairs Processor: -> Pairs: MAX(N(L(s(x)),L(s(y)))) -> MAX(N(L(x),L(y))) -> Rules: max(L(x)) -> x max(N(L(0),L(y))) -> y max(N(L(s(x)),L(s(y)))) -> s(max(N(L(x),L(y)))) max(N(L(x),N(y,z))) -> max(N(L(x),L(max(N(y,z))))) -> Usable rules: Empty ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [L](X) = 2.X [N](X1,X2) = 2.X1 + 2.X2 [s](X) = 2.X + 2
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