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TRS Stand 20472 pair #381713097
details
property
value
status
complete
benchmark
list-sum-prod-bin-assoc-distr-app.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n014.star.cs.uiowa.edu
space
CiME_04
run statistics
property
value
solver
Wanda
configuration
FirstOrder
runtime (wallclock)
0.342401981354 seconds
cpu usage
0.275050483
max memory
1.0784768E7
stage attributes
key
value
output-size
14755
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_FirstOrder /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES We consider the system theBenchmark. We are asked to determine termination of the following first-order TRS. !940 : [] --> o !plus : [o * o] --> o !times : [o * o] --> o 0 : [o] --> o 1 : [o] --> o app : [o * o] --> o cons : [o * o] --> o nil : [] --> o prod : [o] --> o sum : [o] --> o 0(!940) => !940 !plus(X, !940) => X !plus(!940, X) => X !plus(0(X), 0(Y)) => 0(!plus(X, Y)) !plus(0(X), 1(Y)) => 1(!plus(X, Y)) !plus(1(X), 0(Y)) => 1(!plus(X, Y)) !plus(1(X), 1(Y)) => 0(!plus(!plus(X, Y), 1(!940))) !plus(!plus(X, Y), Z) => !plus(X, !plus(Y, Z)) !times(!940, X) => !940 !times(0(X), Y) => 0(!times(X, Y)) !times(1(X), Y) => !plus(0(!times(X, Y)), Y) !times(!times(X, Y), Z) => !times(X, !times(Y, Z)) !times(X, !plus(Y, Z)) => !plus(!times(X, Y), !times(X, Z)) app(nil, X) => X app(cons(X, Y), Z) => cons(X, app(Y, Z)) sum(nil) => 0(!940) sum(cons(X, Y)) => !plus(X, sum(Y)) sum(app(X, Y)) => !plus(sum(X), sum(Y)) prod(nil) => 1(!940) prod(cons(X, Y)) => !times(X, prod(Y)) prod(app(X, Y)) => !times(prod(X), prod(Y)) We use the dependency pair framework as described in [Kop12, Ch. 6/7], with static dependency pairs (see [KusIsoSakBla09] and the adaptation for AFSMs in [Kop12, Ch. 7.8]). We thus obtain the following dependency pair problem (P_0, R_0, minimal, formative): Dependency Pairs P_0: 0] !plus#(0(X), 0(Y)) =#> 0#(!plus(X, Y)) 1] !plus#(0(X), 0(Y)) =#> !plus#(X, Y) 2] !plus#(0(X), 1(Y)) =#> !plus#(X, Y) 3] !plus#(1(X), 0(Y)) =#> !plus#(X, Y) 4] !plus#(1(X), 1(Y)) =#> 0#(!plus(!plus(X, Y), 1(!940))) 5] !plus#(1(X), 1(Y)) =#> !plus#(!plus(X, Y), 1(!940)) 6] !plus#(1(X), 1(Y)) =#> !plus#(X, Y) 7] !plus#(!plus(X, Y), Z) =#> !plus#(X, !plus(Y, Z)) 8] !plus#(!plus(X, Y), Z) =#> !plus#(Y, Z) 9] !times#(0(X), Y) =#> 0#(!times(X, Y)) 10] !times#(0(X), Y) =#> !times#(X, Y) 11] !times#(1(X), Y) =#> !plus#(0(!times(X, Y)), Y) 12] !times#(1(X), Y) =#> 0#(!times(X, Y)) 13] !times#(1(X), Y) =#> !times#(X, Y) 14] !times#(!times(X, Y), Z) =#> !times#(X, !times(Y, Z)) 15] !times#(!times(X, Y), Z) =#> !times#(Y, Z) 16] !times#(X, !plus(Y, Z)) =#> !plus#(!times(X, Y), !times(X, Z)) 17] !times#(X, !plus(Y, Z)) =#> !times#(X, Y) 18] !times#(X, !plus(Y, Z)) =#> !times#(X, Z) 19] app#(cons(X, Y), Z) =#> app#(Y, Z) 20] sum#(nil) =#> 0#(!940) 21] sum#(cons(X, Y)) =#> !plus#(X, sum(Y)) 22] sum#(cons(X, Y)) =#> sum#(Y) 23] sum#(app(X, Y)) =#> !plus#(sum(X), sum(Y)) 24] sum#(app(X, Y)) =#> sum#(X) 25] sum#(app(X, Y)) =#> sum#(Y) 26] prod#(cons(X, Y)) =#> !times#(X, prod(Y)) 27] prod#(cons(X, Y)) =#> prod#(Y) 28] prod#(app(X, Y)) =#> !times#(prod(X), prod(Y)) 29] prod#(app(X, Y)) =#> prod#(X) 30] prod#(app(X, Y)) =#> prod#(Y) Rules R_0: 0(!940) => !940 !plus(X, !940) => X !plus(!940, X) => X !plus(0(X), 0(Y)) => 0(!plus(X, Y)) !plus(0(X), 1(Y)) => 1(!plus(X, Y)) !plus(1(X), 0(Y)) => 1(!plus(X, Y)) !plus(1(X), 1(Y)) => 0(!plus(!plus(X, Y), 1(!940))) !plus(!plus(X, Y), Z) => !plus(X, !plus(Y, Z)) !times(!940, X) => !940 !times(0(X), Y) => 0(!times(X, Y)) !times(1(X), Y) => !plus(0(!times(X, Y)), Y) !times(!times(X, Y), Z) => !times(X, !times(Y, Z)) !times(X, !plus(Y, Z)) => !plus(!times(X, Y), !times(X, Z)) app(nil, X) => X app(cons(X, Y), Z) => cons(X, app(Y, Z)) sum(nil) => 0(!940)
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