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TRS Stand 20472 pair #381713254
details
property
value
status
complete
benchmark
8.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n010.star.cs.uiowa.edu
space
Secret_06_TRS
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.0770211219788 seconds
cpu usage
0.072103252
max memory
4063232.0
stage attributes
key
value
output-size
2728
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y) (RULES a(y,0) -> b(y,0) b(b(0,y),x) -> y c(c(c(y))) -> c(c(a(a(c(b(0,y)),0),0))) ) Problem 1: Dependency Pairs Processor: -> Pairs: A(y,0) -> B(y,0) C(c(c(y))) -> A(a(c(b(0,y)),0),0) C(c(c(y))) -> A(c(b(0,y)),0) C(c(c(y))) -> C(a(a(c(b(0,y)),0),0)) C(c(c(y))) -> C(c(a(a(c(b(0,y)),0),0))) -> Rules: a(y,0) -> b(y,0) b(b(0,y),x) -> y c(c(c(y))) -> c(c(a(a(c(b(0,y)),0),0))) Problem 1: SCC Processor: -> Pairs: A(y,0) -> B(y,0) C(c(c(y))) -> A(a(c(b(0,y)),0),0) C(c(c(y))) -> A(c(b(0,y)),0) C(c(c(y))) -> C(a(a(c(b(0,y)),0),0)) C(c(c(y))) -> C(c(a(a(c(b(0,y)),0),0))) -> Rules: a(y,0) -> b(y,0) b(b(0,y),x) -> y c(c(c(y))) -> c(c(a(a(c(b(0,y)),0),0))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: C(c(c(y))) -> C(a(a(c(b(0,y)),0),0)) C(c(c(y))) -> C(c(a(a(c(b(0,y)),0),0))) ->->-> Rules: a(y,0) -> b(y,0) b(b(0,y),x) -> y c(c(c(y))) -> c(c(a(a(c(b(0,y)),0),0))) Problem 1: Reduction Pair Processor: -> Pairs: C(c(c(y))) -> C(a(a(c(b(0,y)),0),0)) C(c(c(y))) -> C(c(a(a(c(b(0,y)),0),0))) -> Rules: a(y,0) -> b(y,0) b(b(0,y),x) -> y c(c(c(y))) -> c(c(a(a(c(b(0,y)),0),0))) -> Usable rules: a(y,0) -> b(y,0) b(b(0,y),x) -> y c(c(c(y))) -> c(c(a(a(c(b(0,y)),0),0))) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [a](X1,X2) = X1 [b](X1,X2) = X1 + X2 [c](X) = 2.X + 2 [0] = 0 [C](X) = 2.X Problem 1: SCC Processor: -> Pairs: C(c(c(y))) -> C(c(a(a(c(b(0,y)),0),0))) -> Rules: a(y,0) -> b(y,0) b(b(0,y),x) -> y c(c(c(y))) -> c(c(a(a(c(b(0,y)),0),0))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: C(c(c(y))) -> C(c(a(a(c(b(0,y)),0),0))) ->->-> Rules: a(y,0) -> b(y,0) b(b(0,y),x) -> y
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