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TRS Stand 20472 pair #381713291
details
property
value
status
complete
benchmark
#3.8a.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n021.star.cs.uiowa.edu
space
AG01
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
1.35960793495 seconds
cpu usage
4.105740862
max memory
3.68484352E8
stage attributes
key
value
output-size
4558
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: pred(s(x)) -> x minus(x,0()) -> x minus(x,s(y)) -> pred(minus(x,y)) quot(0(),s(y)) -> 0() quot(s(x),s(y)) -> s(quot(minus(x,y),s(y))) log(s(0())) -> 0() log(s(s(x))) -> s(log(s(quot(x,s(s(0())))))) Proof: DP Processor: DPs: minus#(x,s(y)) -> minus#(x,y) minus#(x,s(y)) -> pred#(minus(x,y)) quot#(s(x),s(y)) -> minus#(x,y) quot#(s(x),s(y)) -> quot#(minus(x,y),s(y)) log#(s(s(x))) -> quot#(x,s(s(0()))) log#(s(s(x))) -> log#(s(quot(x,s(s(0()))))) TRS: pred(s(x)) -> x minus(x,0()) -> x minus(x,s(y)) -> pred(minus(x,y)) quot(0(),s(y)) -> 0() quot(s(x),s(y)) -> s(quot(minus(x,y),s(y))) log(s(0())) -> 0() log(s(s(x))) -> s(log(s(quot(x,s(s(0())))))) TDG Processor: DPs: minus#(x,s(y)) -> minus#(x,y) minus#(x,s(y)) -> pred#(minus(x,y)) quot#(s(x),s(y)) -> minus#(x,y) quot#(s(x),s(y)) -> quot#(minus(x,y),s(y)) log#(s(s(x))) -> quot#(x,s(s(0()))) log#(s(s(x))) -> log#(s(quot(x,s(s(0()))))) TRS: pred(s(x)) -> x minus(x,0()) -> x minus(x,s(y)) -> pred(minus(x,y)) quot(0(),s(y)) -> 0() quot(s(x),s(y)) -> s(quot(minus(x,y),s(y))) log(s(0())) -> 0() log(s(s(x))) -> s(log(s(quot(x,s(s(0())))))) graph: log#(s(s(x))) -> log#(s(quot(x,s(s(0()))))) -> log#(s(s(x))) -> log#(s(quot(x,s(s(0()))))) log#(s(s(x))) -> log#(s(quot(x,s(s(0()))))) -> log#(s(s(x))) -> quot#(x,s(s(0()))) log#(s(s(x))) -> quot#(x,s(s(0()))) -> quot#(s(x),s(y)) -> quot#(minus(x,y),s(y)) log#(s(s(x))) -> quot#(x,s(s(0()))) -> quot#(s(x),s(y)) -> minus#(x,y) quot#(s(x),s(y)) -> quot#(minus(x,y),s(y)) -> quot#(s(x),s(y)) -> quot#(minus(x,y),s(y)) quot#(s(x),s(y)) -> quot#(minus(x,y),s(y)) -> quot#(s(x),s(y)) -> minus#(x,y) quot#(s(x),s(y)) -> minus#(x,y) -> minus#(x,s(y)) -> pred#(minus(x,y)) quot#(s(x),s(y)) -> minus#(x,y) -> minus#(x,s(y)) -> minus#(x,y) minus#(x,s(y)) -> minus#(x,y) -> minus#(x,s(y)) -> pred#(minus(x,y)) minus#(x,s(y)) -> minus#(x,y) -> minus#(x,s(y)) -> minus#(x,y) SCC Processor: #sccs: 3 #rules: 3 #arcs: 10/36 DPs: log#(s(s(x))) -> log#(s(quot(x,s(s(0()))))) TRS: pred(s(x)) -> x minus(x,0()) -> x minus(x,s(y)) -> pred(minus(x,y)) quot(0(),s(y)) -> 0() quot(s(x),s(y)) -> s(quot(minus(x,y),s(y))) log(s(0())) -> 0() log(s(s(x))) -> s(log(s(quot(x,s(s(0())))))) Subterm Criterion Processor: simple projection: pi(s) = [0,0,0] pi(pred) = 0 pi(minus) = 0 pi(quot) = [0,0] pi(log#) = [0,0,0] problem: DPs: TRS: pred(s(x)) -> x minus(x,0()) -> x minus(x,s(y)) -> pred(minus(x,y)) quot(0(),s(y)) -> 0() quot(s(x),s(y)) -> s(quot(minus(x,y),s(y))) log(s(0())) -> 0()
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