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TRS Stand 20472 pair #381713312
details
property
value
status
complete
benchmark
2.52.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n078.star.cs.uiowa.edu
space
SK90
run statistics
property
value
solver
Wanda
configuration
FirstOrder
runtime (wallclock)
0.51025390625 seconds
cpu usage
0.507096863
max memory
2.0410368E7
stage attributes
key
value
output-size
17013
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_FirstOrder /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES We consider the system theBenchmark. We are asked to determine termination of the following first-order TRS. 0 : [] --> o f : [o * o * o] --> o s : [o] --> o f(X, 0, 0) => s(X) f(0, X, 0) => s(X) f(0, 0, X) => s(X) f(s(0), X, Y) => f(0, s(X), s(Y)) f(s(X), s(Y), 0) => f(X, Y, s(0)) f(s(X), 0, s(Y)) => f(X, s(0), Y) f(0, s(0), s(0)) => s(s(0)) f(s(X), s(Y), s(Z)) => f(X, Y, f(s(X), s(Y), Z)) f(0, s(s(X)), s(0)) => f(0, X, s(0)) f(0, s(0), s(s(X))) => f(0, s(0), X) f(0, s(s(X)), s(s(Y))) => f(0, X, f(0, s(s(X)), s(Y))) We use rule removal, following [Kop12, Theorem 2.23]. This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): f(X, 0, 0) >? s(X) f(0, X, 0) >? s(X) f(0, 0, X) >? s(X) f(s(0), X, Y) >? f(0, s(X), s(Y)) f(s(X), s(Y), 0) >? f(X, Y, s(0)) f(s(X), 0, s(Y)) >? f(X, s(0), Y) f(0, s(0), s(0)) >? s(s(0)) f(s(X), s(Y), s(Z)) >? f(X, Y, f(s(X), s(Y), Z)) f(0, s(s(X)), s(0)) >? f(0, X, s(0)) f(0, s(0), s(s(X))) >? f(0, s(0), X) f(0, s(s(X)), s(s(Y))) >? f(0, X, f(0, s(s(X)), s(Y))) about to try horpo We use a recursive path ordering as defined in [Kop12, Chapter 5]. We choose Lex = {f} and Mul = {0, s}, and the following precedence: f > s > 0 With these choices, we have: 1] f(X, 0, 0) >= s(X) because [2], by (Star) 2] f*(X, 0, 0) >= s(X) because f > s and [3], by (Copy) 3] f*(X, 0, 0) >= X because [4], by (Select) 4] X >= X by (Meta) 5] f(0, X, 0) > s(X) because [6], by definition 6] f*(0, X, 0) >= s(X) because f > s and [7], by (Copy) 7] f*(0, X, 0) >= X because [8], by (Select) 8] X >= X by (Meta) 9] f(0, 0, X) > s(X) because [10], by definition 10] f*(0, 0, X) >= s(X) because f > s and [11], by (Copy) 11] f*(0, 0, X) >= X because [12], by (Select) 12] X >= X by (Meta) 13] f(s(0), X, Y) >= f(0, s(X), s(Y)) because [14], by (Star) 14] f*(s(0), X, Y) >= f(0, s(X), s(Y)) because [15], [17], [18] and [20], by (Stat) 15] s(0) > 0 because [16], by definition 16] s*(0) >= 0 because s > 0, by (Copy) 17] f*(s(0), X, Y) >= 0 because f > 0, by (Copy) 18] f*(s(0), X, Y) >= s(X) because f > s and [19], by (Copy) 19] f*(s(0), X, Y) >= X because [8], by (Select) 20] f*(s(0), X, Y) >= s(Y) because f > s and [21], by (Copy) 21] f*(s(0), X, Y) >= Y because [12], by (Select) 22] f(s(X), s(Y), 0) >= f(X, Y, s(0)) because [23], by (Star) 23] f*(s(X), s(Y), 0) >= f(X, Y, s(0)) because [24], [26], [28] and [31], by (Stat) 24] s(X) > X because [25], by definition 25] s*(X) >= X because [4], by (Select) 26] f*(s(X), s(Y), 0) >= X because [27], by (Select) 27] s(X) >= X because [25], by (Star) 28] f*(s(X), s(Y), 0) >= Y because [29], by (Select) 29] s(Y) >= Y because [30], by (Star) 30] s*(Y) >= Y because [8], by (Select) 31] f*(s(X), s(Y), 0) >= s(0) because f > s and [32], by (Copy) 32] f*(s(X), s(Y), 0) >= 0 because f > 0, by (Copy) 33] f(s(X), 0, s(Y)) >= f(X, s(0), Y) because [34], by (Star) 34] f*(s(X), 0, s(Y)) >= f(X, s(0), Y) because [24], [35], [36] and [38], by (Stat) 35] f*(s(X), 0, s(Y)) >= X because [27], by (Select) 36] f*(s(X), 0, s(Y)) >= s(0) because f > s and [37], by (Copy) 37] f*(s(X), 0, s(Y)) >= 0 because f > 0, by (Copy) 38] f*(s(X), 0, s(Y)) >= Y because [39], by (Select) 39] s(Y) >= Y because [40], by (Star) 40] s*(Y) >= Y because [12], by (Select) 41] f(0, s(0), s(0)) >= s(s(0)) because [42], by (Star) 42] f*(0, s(0), s(0)) >= s(s(0)) because f > s and [43], by (Copy) 43] f*(0, s(0), s(0)) >= s(0) because [44], by (Select)
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