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TRS Stand 20472 pair #381713363
details
property
value
status
complete
benchmark
2.03.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n094.star.cs.uiowa.edu
space
SK90
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.457623004913 seconds
cpu usage
0.683892073
max memory
1.119232E8
stage attributes
key
value
output-size
1688
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: minus(minus(x)) -> x minus(h(x)) -> h(minus(x)) minus(f(x,y)) -> f(minus(y),minus(x)) Proof: Matrix Interpretation Processor: dim=1 interpretation: [f](x0, x1) = x0 + x1 + 1, [h](x0) = x0, [minus](x0) = 4x0 + 3 orientation: minus(minus(x)) = 16x + 15 >= x = x minus(h(x)) = 4x + 3 >= 4x + 3 = h(minus(x)) minus(f(x,y)) = 4x + 4y + 7 >= 4x + 4y + 7 = f(minus(y),minus(x)) problem: minus(h(x)) -> h(minus(x)) minus(f(x,y)) -> f(minus(y),minus(x)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [0] [f](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [1] [0 1 1] [0 1 1] [0], [1 0 0] [0] [h](x0) = [0 0 0]x0 + [1] [0 1 1] [0], [1 1 1] [minus](x0) = [0 1 0]x0 [1 0 1] orientation: [1 1 1] [1] [1 1 1] [0] minus(h(x)) = [0 0 0]x + [1] >= [0 0 0]x + [1] = h(minus(x)) [1 1 1] [0] [1 1 1] [0] [1 1 1] [1 1 1] [1] [1 1 1] [1 1 1] [0] minus(f(x,y)) = [0 0 0]x + [0 0 0]y + [1] >= [0 0 0]x + [0 0 0]y + [1] = f(minus(y),minus(x)) [1 1 1] [1 1 1] [0] [1 1 1] [1 1 1] [0] problem: Qed
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