details

property	value
status	complete
benchmark	9.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n039.star.cs.uiowa.edu
space	Secret_06_TRS

run statistics

property	value
solver	ttt2-1.17+nonreach
configuration	ttt2-1.17+nonreach
runtime (wallclock)	0.508087158203 seconds
cpu usage	0.828734346
max memory	1.35499776E8

stage attributes

key	value
output-size	2726
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a(x,y) -> b(x,b(0(),c(y))) c(b(y,c(x))) -> c(c(b(a(0(),0()),y))) b(y,0()) -> y Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [b](x0, x1) = [0 1 1]x0 + [0 0 1]x1 [1 0 1] [0 0 0] , [1 1 0] [0] [c](x0) = [0 0 0]x0 + [0] [0 0 0] [1], [0] [0] = [0] [0], [1 0 0] [1 1 0] [1] [a](x0, x1) = [0 1 1]x0 + [0 0 0]x1 + [0] [1 0 1] [0 1 0] [0] orientation: [1 0 0] [1 1 0] [1] [1 0 0] [1 1 0] a(x,y) = [0 1 1]x + [0 0 0]y + [0] >= [0 1 1]x + [0 0 0]y = b(x,b(0(),c(y))) [1 0 1] [0 1 0] [0] [1 0 1] [0 0 0] [1 1 0] [1 1 1] [1] [1 0 1] [1] c(b(y,c(x))) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]y + [0] = c(c(b(a(0(),0()),y))) [0 0 0] [0 0 0] [1] [0 0 0] [1] [1 0 0] b(y,0()) = [0 1 1]y >= y = y [1 0 1] problem: c(b(y,c(x))) -> c(c(b(a(0(),0()),y))) b(y,0()) -> y Matrix Interpretation Processor: dim=3 interpretation: [1 1 1] [1 1 1] [b](x0, x1) = [0 1 0]x0 + [1 0 0]x1 [1 0 1] [1 0 0] , [1 0 0] [0] [c](x0) = [0 0 1]x0 + [1] [0 0 0] [0], [0] [0] = [0] [0], [1 0 0] [1 0 0] [a](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] orientation: [1 0 1] [1 1 1] [1] [1 1 1] [0] c(b(y,c(x))) = [1 0 0]x + [1 0 1]y + [1] >= [0 0 0]y + [1] = c(c(b(a(0(),0()),y))) [0 0 0] [0 0 0] [0] [0 0 0] [0] [1 1 1] b(y,0()) = [0 1 0]y >= y = y [1 0 1] problem: b(y,0()) -> y Matrix Interpretation Processor: dim=3 interpretation: [1 1 0] [b](x0, x1) = x0 + [0 0 0]x1 [0 0 0] , [0] [0] = [1] [0] orientation: [1] b(y,0()) = y + [0] >= y = y [0] problem: Qed popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Stand 20472