Spaces
Explore
Communities
Statistics
Reports
Cluster
Status
Help
TRS Stand 20472 pair #381713721
details
property
value
status
complete
benchmark
z07.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n111.star.cs.uiowa.edu
space
Zantema_05
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.642555952072 seconds
cpu usage
1.308157758
max memory
1.73146112E8
stage attributes
key
value
output-size
5914
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: f(a(),x) -> f(b(),f(c(),x)) f(a(),f(b(),x)) -> f(b(),f(a(),x)) f(d(),f(c(),x)) -> f(d(),f(a(),x)) f(a(),f(c(),x)) -> f(c(),f(a(),x)) Proof: Extended Uncurrying Processor: application symbol: f symbol table: d ==> d0/0 d1/1 c ==> c0/0 c1/1 b ==> b0/0 b1/1 a ==> a0/0 a1/1 uncurry-rules: f(a0(),x1) -> a1(x1) f(b0(),x3) -> b1(x3) f(c0(),x5) -> c1(x5) f(d0(),x7) -> d1(x7) eta-rules: problem: a1(x) -> b1(c1(x)) a1(b1(x)) -> b1(a1(x)) d1(c1(x)) -> d1(a1(x)) a1(c1(x)) -> c1(a1(x)) f(a0(),x1) -> a1(x1) f(b0(),x3) -> b1(x3) f(c0(),x5) -> c1(x5) f(d0(),x7) -> d1(x7) Matrix Interpretation Processor: dim=1 interpretation: [d1](x0) = x0, [d0] = 0, [c1](x0) = 3x0 + 3, [c0] = 1, [b1](x0) = x0, [b0] = 0, [a1](x0) = 3x0 + 3, [a0] = 0, [f](x0, x1) = x0 + 3x1 + 3 orientation: a1(x) = 3x + 3 >= 3x + 3 = b1(c1(x)) a1(b1(x)) = 3x + 3 >= 3x + 3 = b1(a1(x)) d1(c1(x)) = 3x + 3 >= 3x + 3 = d1(a1(x)) a1(c1(x)) = 9x + 12 >= 9x + 12 = c1(a1(x)) f(a0(),x1) = 3x1 + 3 >= 3x1 + 3 = a1(x1) f(b0(),x3) = 3x3 + 3 >= x3 = b1(x3) f(c0(),x5) = 3x5 + 4 >= 3x5 + 3 = c1(x5) f(d0(),x7) = 3x7 + 3 >= x7 = d1(x7) problem: a1(x) -> b1(c1(x)) a1(b1(x)) -> b1(a1(x)) d1(c1(x)) -> d1(a1(x)) a1(c1(x)) -> c1(a1(x)) f(a0(),x1) -> a1(x1) Matrix Interpretation Processor: dim=1 interpretation: [d1](x0) = 2x0, [c1](x0) = 4x0 + 1, [b1](x0) = x0, [a1](x0) = 4x0 + 1, [a0] = 0, [f](x0, x1) = 2x0 + 4x1 + 5 orientation: a1(x) = 4x + 1 >= 4x + 1 = b1(c1(x)) a1(b1(x)) = 4x + 1 >= 4x + 1 = b1(a1(x))
popout
output may be truncated. 'popout' for the full output.
job log
popout
actions
all output
return to TRS Stand 20472