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TRS Stand 20472 pair #381713969
details
property
value
status
complete
benchmark
#3.24.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n008.star.cs.uiowa.edu
space
AG01
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.447212934494 seconds
cpu usage
0.64699213
max memory
1.06897408E8
stage attributes
key
value
output-size
1269
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: f(0()) -> s(0()) f(s(0())) -> s(0()) f(s(s(x))) -> f(f(s(x))) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [0] [s](x0) = [0 1 0]x0 + [0] [0 0 0] [1], [1 1 0] [0] [f](x0) = [0 0 0]x0 + [1] [1 1 0] [0], [0] [0] = [1] [0] orientation: [1] [0] f(0()) = [1] >= [1] = s(0()) [1] [1] [1] [0] f(s(0())) = [1] >= [1] = s(0()) [1] [1] [1 1 1] [1] [1 1 1] [1] f(s(s(x))) = [0 0 0]x + [1] >= [0 0 0]x + [1] = f(f(s(x))) [1 1 1] [1] [1 1 1] [1] problem: f(s(s(x))) -> f(f(s(x))) Matrix Interpretation Processor: dim=1 interpretation: [s](x0) = x0 + 4, [f](x0) = x0 + 3 orientation: f(s(s(x))) = x + 11 >= x + 10 = f(f(s(x))) problem: Qed
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