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TRS Stand 20472 pair #381714002
details
property
value
status
complete
benchmark
4.52.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n099.star.cs.uiowa.edu
space
SK90
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.697777032852 seconds
cpu usage
1.509179438
max memory
1.77758208E8
stage attributes
key
value
output-size
4895
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: s(a()) -> a() s(s(x)) -> x s(f(x,y)) -> f(s(y),s(x)) s(g(x,y)) -> g(s(x),s(y)) f(x,a()) -> x f(a(),y) -> y f(g(x,y),g(u,v)) -> g(f(x,u),f(y,v)) g(a(),a()) -> a() Proof: Matrix Interpretation Processor: dim=1 interpretation: [g](x0, x1) = 2x0 + x1 + 4, [f](x0, x1) = x0 + x1, [s](x0) = x0, [a] = 0 orientation: s(a()) = 0 >= 0 = a() s(s(x)) = x >= x = x s(f(x,y)) = x + y >= x + y = f(s(y),s(x)) s(g(x,y)) = 2x + y + 4 >= 2x + y + 4 = g(s(x),s(y)) f(x,a()) = x >= x = x f(a(),y) = y >= y = y f(g(x,y),g(u,v)) = 2u + v + 2x + y + 8 >= 2u + v + 2x + y + 4 = g(f(x,u),f(y,v)) g(a(),a()) = 4 >= 0 = a() problem: s(a()) -> a() s(s(x)) -> x s(f(x,y)) -> f(s(y),s(x)) s(g(x,y)) -> g(s(x),s(y)) f(x,a()) -> x f(a(),y) -> y Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [1] [g](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 0] [0], [1 0 0] [1 0 0] [f](x0, x1) = [1 1 0]x0 + [1 1 0]x1 [0 0 1] [0 0 1] , [s](x0) = x0 , [1] [a] = [0] [0] orientation: [1] [1] s(a()) = [0] >= [0] = a() [0] [0] s(s(x)) = x >= x = x [1 0 0] [1 0 0] [1 0 0] [1 0 0] s(f(x,y)) = [1 1 0]x + [1 1 0]y >= [1 1 0]x + [1 1 0]y = f(s(y),s(x)) [0 0 1] [0 0 1] [0 0 1] [0 0 1] [1 0 0] [1 0 0] [1] [1 0 0] [1 0 0] [1] s(g(x,y)) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0 0 0]y + [0] = g(s(x),s(y)) [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] [0] [1 0 0] [1] f(x,a()) = [1 1 0]x + [1] >= x = x [0 0 1] [0] [1 0 0] [1] f(a(),y) = [1 1 0]y + [1] >= y = y [0 0 1] [0] problem: s(a()) -> a() s(s(x)) -> x s(f(x,y)) -> f(s(y),s(x)) s(g(x,y)) -> g(s(x),s(y)) Matrix Interpretation Processor: dim=1
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