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TRS Stand 20472 pair #381714006
details
property
value
status
complete
benchmark
thiemann09.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n078.star.cs.uiowa.edu
space
AProVE_07
run statistics
property
value
solver
Wanda
configuration
FirstOrder
runtime (wallclock)
0.810869932175 seconds
cpu usage
0.805931621
max memory
2.8397568E7
stage attributes
key
value
output-size
1124
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_FirstOrder /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE We consider the system theBenchmark. We are asked to determine termination of the following first-order TRS. 0 : [] --> o ack : [o * o] --> o div : [o * o] --> o false : [] --> o minus : [o * o] --> o p : [o] --> o plus : [o * o] --> o quot : [o * o * o] --> o s : [o] --> o true : [] --> o zero : [o] --> o minus(minus(X, Y), Z) => minus(X, plus(Y, Z)) minus(0, X) => 0 minus(X, 0) => X minus(s(X), s(Y)) => minus(X, Y) plus(0, X) => X plus(s(X), Y) => plus(X, s(Y)) plus(s(X), Y) => s(plus(Y, X)) zero(s(X)) => false zero(0) => true p(s(X)) => X p(0) => 0 div(X, Y) => quot(X, Y, 0) quot(s(X), s(Y), Z) => quot(minus(p(ack(0, X)), Y), s(Y), s(Z)) quot(0, s(X), Y) => Y ack(0, X) => s(X) ack(0, X) => plus(X, s(0)) ack(s(X), 0) => ack(X, s(0)) ack(s(X), s(Y)) => ack(X, ack(s(X), Y))
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