details

property	value
status	complete
benchmark	4.40.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n101.star.cs.uiowa.edu
space	SK90

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	2.68923711777 seconds
cpu usage	6.933768844
max memory	3.25787648E8

stage attributes

key	value
output-size	6449
starexec-result	NO

output

/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) Overlay + Local Confluence [EQUIVALENT, 4 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 0 ms] (4) QDP (5) TransformationProof [EQUIVALENT, 0 ms] (6) QDP (7) TransformationProof [EQUIVALENT, 0 ms] (8) QDP (9) MNOCProof [EQUIVALENT, 0 ms] (10) QDP (11) NonTerminationLoopProof [COMPLETE, 25 ms] (12) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(f(f(a, x), y), z) -> f(f(x, z), f(y, z)) f(f(b, x), y) -> x f(c, y) -> y Q is empty. ---------------------------------------- (1) Overlay + Local Confluence (EQUIVALENT) The TRS is overlay and locally confluent. By [NOC] we can switch to innermost. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(f(f(a, x), y), z) -> f(f(x, z), f(y, z)) f(f(b, x), y) -> x f(c, y) -> y The set Q consists of the following terms: f(f(f(a, x0), x1), x2) f(f(b, x0), x1) f(c, x0) ---------------------------------------- (3) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: F(f(f(a, x), y), z) -> F(f(x, z), f(y, z)) F(f(f(a, x), y), z) -> F(x, z) F(f(f(a, x), y), z) -> F(y, z) The TRS R consists of the following rules: f(f(f(a, x), y), z) -> f(f(x, z), f(y, z)) f(f(b, x), y) -> x f(c, y) -> y The set Q consists of the following terms: f(f(f(a, x0), x1), x2) f(f(b, x0), x1) f(c, x0) We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (5) TransformationProof (EQUIVALENT) By forward instantiating [JAR06] the rule F(f(f(a, x), y), z) -> F(x, z) we obtained the following new rules [LPAR04]: (F(f(f(a, f(f(a, y_0), y_1)), x1), x2) -> F(f(f(a, y_0), y_1), x2),F(f(f(a, f(f(a, y_0), y_1)), x1), x2) -> F(f(f(a, y_0), y_1), x2)) ---------------------------------------- popout

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job log

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actions

all output return to TRS Stand 20472