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TRS Stand 20472 pair #381715127
details
property
value
status
complete
benchmark
Ex14_Luc06_C.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n016.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.03670692444 seconds
cpu usage
4.817201235
max memory
3.3705984E8
stage attributes
key
value
output-size
7099
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSToCSRProof [EQUIVALENT, 0 ms] (2) CSR (3) CSRRRRProof [EQUIVALENT, 13 ms] (4) CSR (5) CSDependencyPairsProof [EQUIVALENT, 0 ms] (6) QCSDP (7) QCSDPInstantiationProcessor [EQUIVALENT, 0 ms] (8) QCSDP (9) QCSUsableRulesProof [EQUIVALENT, 0 ms] (10) QCSDP (11) QCSDPInstantiationProcessor [EQUIVALENT, 0 ms] (12) QCSDP (13) QCSDependencyGraphProof [EQUIVALENT, 4 ms] (14) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: active(h(X)) -> mark(g(X, X)) active(g(a, X)) -> mark(f(b, X)) active(f(X, X)) -> mark(h(a)) active(a) -> mark(b) active(h(X)) -> h(active(X)) active(g(X1, X2)) -> g(active(X1), X2) active(f(X1, X2)) -> f(active(X1), X2) h(mark(X)) -> mark(h(X)) g(mark(X1), X2) -> mark(g(X1, X2)) f(mark(X1), X2) -> mark(f(X1, X2)) proper(h(X)) -> h(proper(X)) proper(g(X1, X2)) -> g(proper(X1), proper(X2)) proper(a) -> ok(a) proper(f(X1, X2)) -> f(proper(X1), proper(X2)) proper(b) -> ok(b) h(ok(X)) -> ok(h(X)) g(ok(X1), ok(X2)) -> ok(g(X1, X2)) f(ok(X1), ok(X2)) -> ok(f(X1, X2)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Q is empty. ---------------------------------------- (1) QTRSToCSRProof (EQUIVALENT) The following Q TRS is given: Q restricted rewrite system: The TRS R consists of the following rules: active(h(X)) -> mark(g(X, X)) active(g(a, X)) -> mark(f(b, X)) active(f(X, X)) -> mark(h(a)) active(a) -> mark(b) active(h(X)) -> h(active(X)) active(g(X1, X2)) -> g(active(X1), X2) active(f(X1, X2)) -> f(active(X1), X2) h(mark(X)) -> mark(h(X)) g(mark(X1), X2) -> mark(g(X1, X2)) f(mark(X1), X2) -> mark(f(X1, X2)) proper(h(X)) -> h(proper(X)) proper(g(X1, X2)) -> g(proper(X1), proper(X2)) proper(a) -> ok(a) proper(f(X1, X2)) -> f(proper(X1), proper(X2)) proper(b) -> ok(b) h(ok(X)) -> ok(h(X)) g(ok(X1), ok(X2)) -> ok(g(X1, X2)) f(ok(X1), ok(X2)) -> ok(f(X1, X2)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Q is empty. Special symbols used for the transformation (see [GM04]): top: top_1, active: active_1, mark: mark_1, ok: ok_1, proper: proper_1 The replacement map contains the following entries: h: {1} g: {1} a: empty set f: {1} b: empty set The QTRS contained all rules created by the complete Giesl-Middeldorp transformation. Therefore, the inverse transformation is complete (and sound). ----------------------------------------
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