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TRS Stand 20472 pair #381715422
details
property
value
status
complete
benchmark
LISTUTILITIES_nosorts-noand_Z.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n112.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.38893604279 seconds
cpu usage
6.255561609
max memory
3.89414912E8
stage attributes
key
value
output-size
26284
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) QDP (5) TransformationProof [EQUIVALENT, 0 ms] (6) QDP (7) TransformationProof [EQUIVALENT, 0 ms] (8) QDP (9) DependencyGraphProof [EQUIVALENT, 0 ms] (10) QDP (11) TransformationProof [EQUIVALENT, 0 ms] (12) QDP (13) TransformationProof [EQUIVALENT, 0 ms] (14) QDP (15) DependencyGraphProof [EQUIVALENT, 0 ms] (16) QDP (17) QDPOrderProof [EQUIVALENT, 35 ms] (18) QDP (19) DependencyGraphProof [EQUIVALENT, 0 ms] (20) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: U11(tt, N, XS) -> U12(tt, activate(N), activate(XS)) U12(tt, N, XS) -> snd(splitAt(activate(N), activate(XS))) U21(tt, X) -> U22(tt, activate(X)) U22(tt, X) -> activate(X) U31(tt, N) -> U32(tt, activate(N)) U32(tt, N) -> activate(N) U41(tt, N, XS) -> U42(tt, activate(N), activate(XS)) U42(tt, N, XS) -> head(afterNth(activate(N), activate(XS))) U51(tt, Y) -> U52(tt, activate(Y)) U52(tt, Y) -> activate(Y) U61(tt, N, X, XS) -> U62(tt, activate(N), activate(X), activate(XS)) U62(tt, N, X, XS) -> U63(tt, activate(N), activate(X), activate(XS)) U63(tt, N, X, XS) -> U64(splitAt(activate(N), activate(XS)), activate(X)) U64(pair(YS, ZS), X) -> pair(cons(activate(X), YS), ZS) U71(tt, XS) -> U72(tt, activate(XS)) U72(tt, XS) -> activate(XS) U81(tt, N, XS) -> U82(tt, activate(N), activate(XS)) U82(tt, N, XS) -> fst(splitAt(activate(N), activate(XS))) afterNth(N, XS) -> U11(tt, N, XS) fst(pair(X, Y)) -> U21(tt, X) head(cons(N, XS)) -> U31(tt, N) natsFrom(N) -> cons(N, n__natsFrom(s(N))) sel(N, XS) -> U41(tt, N, XS) snd(pair(X, Y)) -> U51(tt, Y) splitAt(0, XS) -> pair(nil, XS) splitAt(s(N), cons(X, XS)) -> U61(tt, N, X, activate(XS)) tail(cons(N, XS)) -> U71(tt, activate(XS)) take(N, XS) -> U81(tt, N, XS) natsFrom(X) -> n__natsFrom(X) activate(n__natsFrom(X)) -> natsFrom(X) activate(X) -> X Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: U11^1(tt, N, XS) -> U12^1(tt, activate(N), activate(XS)) U11^1(tt, N, XS) -> ACTIVATE(N) U11^1(tt, N, XS) -> ACTIVATE(XS) U12^1(tt, N, XS) -> SND(splitAt(activate(N), activate(XS))) U12^1(tt, N, XS) -> SPLITAT(activate(N), activate(XS)) U12^1(tt, N, XS) -> ACTIVATE(N) U12^1(tt, N, XS) -> ACTIVATE(XS) U21^1(tt, X) -> U22^1(tt, activate(X)) U21^1(tt, X) -> ACTIVATE(X) U22^1(tt, X) -> ACTIVATE(X) U31^1(tt, N) -> U32^1(tt, activate(N)) U31^1(tt, N) -> ACTIVATE(N)
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