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TRS Stand 20472 pair #381715462
details
property
value
status
complete
benchmark
MYNAT_nosorts_noand_GM.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n092.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.98851799965 seconds
cpu usage
4.675870446
max memory
2.26758656E8
stage attributes
key
value
output-size
5282
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 250 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 0 ms] (4) QTRS (5) RisEmptyProof [EQUIVALENT, 3 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a__U11(tt, M, N) -> a__U12(tt, M, N) a__U12(tt, M, N) -> s(a__plus(mark(N), mark(M))) a__U21(tt, M, N) -> a__U22(tt, M, N) a__U22(tt, M, N) -> a__plus(a__x(mark(N), mark(M)), mark(N)) a__plus(N, 0) -> mark(N) a__plus(N, s(M)) -> a__U11(tt, M, N) a__x(N, 0) -> 0 a__x(N, s(M)) -> a__U21(tt, M, N) mark(U11(X1, X2, X3)) -> a__U11(mark(X1), X2, X3) mark(U12(X1, X2, X3)) -> a__U12(mark(X1), X2, X3) mark(plus(X1, X2)) -> a__plus(mark(X1), mark(X2)) mark(U21(X1, X2, X3)) -> a__U21(mark(X1), X2, X3) mark(U22(X1, X2, X3)) -> a__U22(mark(X1), X2, X3) mark(x(X1, X2)) -> a__x(mark(X1), mark(X2)) mark(tt) -> tt mark(s(X)) -> s(mark(X)) mark(0) -> 0 a__U11(X1, X2, X3) -> U11(X1, X2, X3) a__U12(X1, X2, X3) -> U12(X1, X2, X3) a__plus(X1, X2) -> plus(X1, X2) a__U21(X1, X2, X3) -> U21(X1, X2, X3) a__U22(X1, X2, X3) -> U22(X1, X2, X3) a__x(X1, X2) -> x(X1, X2) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: a__U11/3(YES,YES,YES) tt/0) a__U12/3(YES,YES,YES) s/1(YES) a__plus/2(YES,YES) mark/1)YES( a__U21/3(YES,YES,YES) a__U22/3(YES,YES,YES) a__x/2(YES,YES) 0/0) U11/3(YES,YES,YES) U12/3(YES,YES,YES) plus/2(YES,YES) U21/3(YES,YES,YES) U22/3(YES,YES,YES) x/2(YES,YES) Quasi precedence: [a__U21_3, a__U22_3, a__x_2, U21_3, U22_3, x_2] > [a__U11_3, a__U12_3, a__plus_2, U11_3, U12_3, plus_2] > [tt, s_1] 0 > [tt, s_1] Status: a__U11_3: multiset status tt: multiset status a__U12_3: multiset status s_1: multiset status a__plus_2: multiset status a__U21_3: [3,2,1] a__U22_3: [3,2,1] a__x_2: [1,2] 0: multiset status U11_3: multiset status U12_3: multiset status plus_2: multiset status U21_3: [3,2,1] U22_3: [3,2,1] x_2: [1,2] With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly:
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