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TRS Stand 20472 pair #381716119
details
property
value
status
complete
benchmark
PEANO_nosorts_noand_GM.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n026.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.907839775085 seconds
cpu usage
2.262126821
max memory
2.5831424E8
stage attributes
key
value
output-size
16355
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a__U11(tt(),M,N) -> a__U12(tt(),M,N) a__U12(tt(),M,N) -> s(a__plus(mark(N),mark(M))) a__plus(N,0()) -> mark(N) a__plus(N,s(M)) -> a__U11(tt(),M,N) mark(U11(X1,X2,X3)) -> a__U11(mark(X1),X2,X3) mark(U12(X1,X2,X3)) -> a__U12(mark(X1),X2,X3) mark(plus(X1,X2)) -> a__plus(mark(X1),mark(X2)) mark(tt()) -> tt() mark(s(X)) -> s(mark(X)) mark(0()) -> 0() a__U11(X1,X2,X3) -> U11(X1,X2,X3) a__U12(X1,X2,X3) -> U12(X1,X2,X3) a__plus(X1,X2) -> plus(X1,X2) Proof: Matrix Interpretation Processor: dim=1 interpretation: [plus](x0, x1) = x0 + 2x1, [U12](x0, x1, x2) = x0 + 2x1 + x2, [U11](x0, x1, x2) = x0 + 2x1 + x2, [0] = 0, [s](x0) = x0 + 4, [a__plus](x0, x1) = x0 + 2x1, [mark](x0) = x0, [a__U12](x0, x1, x2) = x0 + 2x1 + x2, [a__U11](x0, x1, x2) = x0 + 2x1 + x2, [tt] = 4 orientation: a__U11(tt(),M,N) = 2M + N + 4 >= 2M + N + 4 = a__U12(tt(),M,N) a__U12(tt(),M,N) = 2M + N + 4 >= 2M + N + 4 = s(a__plus(mark(N),mark(M))) a__plus(N,0()) = N >= N = mark(N) a__plus(N,s(M)) = 2M + N + 8 >= 2M + N + 4 = a__U11(tt(),M,N) mark(U11(X1,X2,X3)) = X1 + 2X2 + X3 >= X1 + 2X2 + X3 = a__U11(mark(X1),X2,X3) mark(U12(X1,X2,X3)) = X1 + 2X2 + X3 >= X1 + 2X2 + X3 = a__U12(mark(X1),X2,X3) mark(plus(X1,X2)) = X1 + 2X2 >= X1 + 2X2 = a__plus(mark(X1),mark(X2)) mark(tt()) = 4 >= 4 = tt() mark(s(X)) = X + 4 >= X + 4 = s(mark(X)) mark(0()) = 0 >= 0 = 0() a__U11(X1,X2,X3) = X1 + 2X2 + X3 >= X1 + 2X2 + X3 = U11(X1,X2,X3) a__U12(X1,X2,X3) = X1 + 2X2 + X3 >= X1 + 2X2 + X3 = U12(X1,X2,X3) a__plus(X1,X2) = X1 + 2X2 >= X1 + 2X2 = plus(X1,X2) problem: a__U11(tt(),M,N) -> a__U12(tt(),M,N) a__U12(tt(),M,N) -> s(a__plus(mark(N),mark(M))) a__plus(N,0()) -> mark(N) mark(U11(X1,X2,X3)) -> a__U11(mark(X1),X2,X3) mark(U12(X1,X2,X3)) -> a__U12(mark(X1),X2,X3) mark(plus(X1,X2)) -> a__plus(mark(X1),mark(X2)) mark(tt()) -> tt() mark(s(X)) -> s(mark(X)) mark(0()) -> 0() a__U11(X1,X2,X3) -> U11(X1,X2,X3) a__U12(X1,X2,X3) -> U12(X1,X2,X3) a__plus(X1,X2) -> plus(X1,X2) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [plus](x0, x1) = [1 0 0]x0 + [0 1 0]x1 [1 0 0] [1 0 0] , [1 0 0] [1 0 1] [1 0 0] [U12](x0, x1, x2) = [0 0 0]x0 + [1 0 0]x1 + [1 0 0]x2 [0 0 0] [1 0 1] [1 0 0] , [1 0 0] [1 0 1] [1 0 0] [1] [U11](x0, x1, x2) = [0 0 0]x0 + [1 0 0]x1 + [1 0 0]x2 + [0] [0 0 0] [1 0 1] [1 0 0] [0],
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