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TRS Stand 20472 pair #381716144
details
property
value
status
complete
benchmark
Ex23_Luc06_GM.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n103.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.533122062683 seconds
cpu usage
0.900906716
max memory
1.44306176E8
stage attributes
key
value
output-size
3329
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a__f(f(a())) -> c(f(g(f(a())))) mark(f(X)) -> a__f(mark(X)) mark(a()) -> a() mark(c(X)) -> c(X) mark(g(X)) -> g(mark(X)) a__f(X) -> f(X) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1] [mark](x0) = [0 1 0]x0 + [0] [0 1 0] [0], [1 0 0] [c](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [g](x0) = [0 0 0]x0 [0 0 0] , [1 1 0] [0] [a__f](x0) = [0 0 0]x0 + [1] [0 0 0] [1], [1 1 0] [0] [f](x0) = [0 0 0]x0 + [1] [0 0 0] [1], [0] [a] = [0] [0] orientation: [1] [0] a__f(f(a())) = [1] >= [0] = c(f(g(f(a())))) [1] [0] [1 1 0] [1] [1 1 0] [1] mark(f(X)) = [0 0 0]X + [1] >= [0 0 0]X + [1] = a__f(mark(X)) [0 0 0] [1] [0 0 0] [1] [1] [0] mark(a()) = [0] >= [0] = a() [0] [0] [1 0 0] [1] [1 0 0] mark(c(X)) = [0 0 0]X + [0] >= [0 0 0]X = c(X) [0 0 0] [0] [0 0 0] [1 0 0] [1] [1 0 0] [1] mark(g(X)) = [0 0 0]X + [0] >= [0 0 0]X + [0] = g(mark(X)) [0 0 0] [0] [0 0 0] [0] [1 1 0] [0] [1 1 0] [0] a__f(X) = [0 0 0]X + [1] >= [0 0 0]X + [1] = f(X) [0 0 0] [1] [0 0 0] [1] problem: mark(f(X)) -> a__f(mark(X)) mark(g(X)) -> g(mark(X)) a__f(X) -> f(X) Matrix Interpretation Processor: dim=1 interpretation: [mark](x0) = 4x0 + 3, [g](x0) = 7x0 + 6, [a__f](x0) = 4x0 + 7, [f](x0) = 4x0 + 4 orientation: mark(f(X)) = 16X + 19 >= 16X + 19 = a__f(mark(X)) mark(g(X)) = 28X + 27 >= 28X + 27 = g(mark(X)) a__f(X) = 4X + 7 >= 4X + 4 = f(X) problem: mark(f(X)) -> a__f(mark(X)) mark(g(X)) -> g(mark(X)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [mark](x0) = [0 0 1]x0 [0 1 0] , [1 0 0] [0] [g](x0) = [0 1 1]x0 + [1] [0 1 1] [1],
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