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TRS Stand 20472 pair #381716294
details
property
value
status
complete
benchmark
Ex15_Luc06_C.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n002.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
1.08754110336 seconds
cpu usage
2.923066751
max memory
2.31284736E8
stage attributes
key
value
output-size
10917
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: active(f(f(a()))) -> mark(f(g(f(a())))) active(g(X)) -> g(active(X)) g(mark(X)) -> mark(g(X)) proper(f(X)) -> f(proper(X)) proper(a()) -> ok(a()) proper(g(X)) -> g(proper(X)) f(ok(X)) -> ok(f(X)) g(ok(X)) -> ok(g(X)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [top](x0) = [1 1 0]x0 [0 0 0] , [ok](x0) = x0 , [proper](x0) = x0 , [1 1 0] [mark](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [g](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [active](x0) = [0 0 0]x0 [0 0 0] , [1 0 1] [f](x0) = [0 0 0]x0 [0 1 0] , [0] [a] = [1] [0] orientation: [1] [0] active(f(f(a()))) = [0] >= [0] = mark(f(g(f(a())))) [0] [0] [1 0 0] [1 0 0] active(g(X)) = [0 0 0]X >= [0 0 0]X = g(active(X)) [0 0 0] [0 0 0] [1 1 0] [1 0 0] g(mark(X)) = [0 0 0]X >= [0 0 0]X = mark(g(X)) [0 0 0] [0 0 0] [1 0 1] [1 0 1] proper(f(X)) = [0 0 0]X >= [0 0 0]X = f(proper(X)) [0 1 0] [0 1 0] [0] [0] proper(a()) = [1] >= [1] = ok(a()) [0] [0] [1 0 0] [1 0 0] proper(g(X)) = [0 0 0]X >= [0 0 0]X = g(proper(X)) [0 0 0] [0 0 0] [1 0 1] [1 0 1] f(ok(X)) = [0 0 0]X >= [0 0 0]X = ok(f(X)) [0 1 0] [0 1 0] [1 0 0] [1 0 0] g(ok(X)) = [0 0 0]X >= [0 0 0]X = ok(g(X)) [0 0 0] [0 0 0] [1 1 0] [1 0 0] top(mark(X)) = [1 1 0]X >= [1 1 0]X = top(proper(X)) [0 0 0] [0 0 0] [1 0 0] [1 0 0] top(ok(X)) = [1 1 0]X >= [1 0 0]X = top(active(X)) [0 0 0] [0 0 0] problem: active(g(X)) -> g(active(X)) g(mark(X)) -> mark(g(X)) proper(f(X)) -> f(proper(X)) proper(a()) -> ok(a())
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