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TRS Stand 20472 pair #381716414
details
property
value
status
complete
benchmark
ExIntrod_GM01_C.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n102.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
4.33789205551 seconds
cpu usage
15.437327231
max memory
4.96381952E8
stage attributes
key
value
output-size
53504
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: active(incr(nil())) -> mark(nil()) active(incr(cons(X,L))) -> mark(cons(s(X),incr(L))) active(adx(nil())) -> mark(nil()) active(adx(cons(X,L))) -> mark(incr(cons(X,adx(L)))) active(nats()) -> mark(adx(zeros())) active(zeros()) -> mark(cons(0(),zeros())) active(head(cons(X,L))) -> mark(X) active(tail(cons(X,L))) -> mark(L) active(incr(X)) -> incr(active(X)) active(cons(X1,X2)) -> cons(active(X1),X2) active(s(X)) -> s(active(X)) active(adx(X)) -> adx(active(X)) active(head(X)) -> head(active(X)) active(tail(X)) -> tail(active(X)) incr(mark(X)) -> mark(incr(X)) cons(mark(X1),X2) -> mark(cons(X1,X2)) s(mark(X)) -> mark(s(X)) adx(mark(X)) -> mark(adx(X)) head(mark(X)) -> mark(head(X)) tail(mark(X)) -> mark(tail(X)) proper(incr(X)) -> incr(proper(X)) proper(nil()) -> ok(nil()) proper(cons(X1,X2)) -> cons(proper(X1),proper(X2)) proper(s(X)) -> s(proper(X)) proper(adx(X)) -> adx(proper(X)) proper(nats()) -> ok(nats()) proper(zeros()) -> ok(zeros()) proper(0()) -> ok(0()) proper(head(X)) -> head(proper(X)) proper(tail(X)) -> tail(proper(X)) incr(ok(X)) -> ok(incr(X)) cons(ok(X1),ok(X2)) -> ok(cons(X1,X2)) s(ok(X)) -> ok(s(X)) adx(ok(X)) -> ok(adx(X)) head(ok(X)) -> ok(head(X)) tail(ok(X)) -> ok(tail(X)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Proof: Matrix Interpretation Processor: dim=1 interpretation: [top](x0) = x0 + 5, [ok](x0) = x0, [proper](x0) = x0, [tail](x0) = 2x0 + 1, [head](x0) = 4x0, [0] = 0, [zeros] = 0, [nats] = 4, [adx](x0) = 2x0, [s](x0) = x0, [cons](x0, x1) = x0 + x1, [mark](x0) = x0, [active](x0) = x0, [incr](x0) = x0, [nil] = 0 orientation: active(incr(nil())) = 0 >= 0 = mark(nil()) active(incr(cons(X,L))) = L + X >= L + X = mark(cons(s(X),incr(L))) active(adx(nil())) = 0 >= 0 = mark(nil()) active(adx(cons(X,L))) = 2L + 2X >= 2L + X = mark(incr(cons(X,adx(L)))) active(nats()) = 4 >= 0 = mark(adx(zeros())) active(zeros()) = 0 >= 0 = mark(cons(0(),zeros())) active(head(cons(X,L))) = 4L + 4X >= X = mark(X) active(tail(cons(X,L))) = 2L + 2X + 1 >= L = mark(L) active(incr(X)) = X >= X = incr(active(X))
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