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TRS Stand 20472 pair #381716427
details
property
value
status
complete
benchmark
ExProp7_Luc06_L.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n102.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.67675614357 seconds
cpu usage
3.664383059
max memory
1.9124224E8
stage attributes
key
value
output-size
1870
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (2) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(0) -> cons(0) f(s(0)) -> f(p(s(0))) p(s(X)) -> X Q is empty. ---------------------------------------- (1) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 2. This implies Q-termination of R. The following rules were used to construct the certificate: f(0) -> cons(0) f(s(0)) -> f(p(s(0))) p(s(X)) -> X The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 1, 3, 5, 6, 7, 8, 17, 18, 19, 20 Node 1 is start node and node 3 is final node. Those nodes are connected through the following edges: * 1 to 5 labelled cons_1(0)* 1 to 6 labelled f_1(0)* 1 to 3 labelled f_1(0), 0(0), cons_1(0), s_1(0), p_1(0), f_1(1), 0(1), cons_1(1), s_1(1), p_1(1)* 1 to 17 labelled cons_1(1)* 1 to 18 labelled f_1(1), cons_1(2)* 1 to 1 labelled cons_1(1)* 3 to 3 labelled #_1(0)* 5 to 3 labelled 0(0)* 6 to 7 labelled p_1(0)* 6 to 3 labelled 0(1)* 7 to 8 labelled s_1(0)* 8 to 3 labelled 0(0)* 17 to 3 labelled 0(1)* 18 to 19 labelled p_1(1)* 18 to 3 labelled 0(2)* 19 to 20 labelled s_1(1)* 20 to 3 labelled 0(1) ---------------------------------------- (2) YES
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