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TRS Stand 20472 pair #381716594
details
property
value
status
complete
benchmark
Ex25_Luc06_C.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n098.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
2.85691595078 seconds
cpu usage
10.11598968
max memory
1.039659008E9
stage attributes
key
value
output-size
4588
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: active(f(f(X))) -> mark(c(f(g(f(X))))) active(c(X)) -> mark(d(X)) active(h(X)) -> mark(c(d(X))) active(f(X)) -> f(active(X)) active(h(X)) -> h(active(X)) f(mark(X)) -> mark(f(X)) h(mark(X)) -> mark(h(X)) proper(f(X)) -> f(proper(X)) proper(c(X)) -> c(proper(X)) proper(g(X)) -> g(proper(X)) proper(d(X)) -> d(proper(X)) proper(h(X)) -> h(proper(X)) f(ok(X)) -> ok(f(X)) c(ok(X)) -> ok(c(X)) g(ok(X)) -> ok(g(X)) d(ok(X)) -> ok(d(X)) h(ok(X)) -> ok(h(X)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Proof: Matrix Interpretation Processor: dim=1 interpretation: [top](x0) = 4x0 + 7, [ok](x0) = 4x0 + 2, [proper](x0) = x0, [h](x0) = 5x0, [d](x0) = 5x0, [mark](x0) = x0, [c](x0) = 4x0, [g](x0) = x0, [active](x0) = 4x0, [f](x0) = 2x0 orientation: active(f(f(X))) = 16X >= 16X = mark(c(f(g(f(X))))) active(c(X)) = 16X >= 5X = mark(d(X)) active(h(X)) = 20X >= 20X = mark(c(d(X))) active(f(X)) = 8X >= 8X = f(active(X)) active(h(X)) = 20X >= 20X = h(active(X)) f(mark(X)) = 2X >= 2X = mark(f(X)) h(mark(X)) = 5X >= 5X = mark(h(X)) proper(f(X)) = 2X >= 2X = f(proper(X)) proper(c(X)) = 4X >= 4X = c(proper(X)) proper(g(X)) = X >= X = g(proper(X)) proper(d(X)) = 5X >= 5X = d(proper(X)) proper(h(X)) = 5X >= 5X = h(proper(X)) f(ok(X)) = 8X + 4 >= 8X + 2 = ok(f(X)) c(ok(X)) = 16X + 8 >= 16X + 2 = ok(c(X)) g(ok(X)) = 4X + 2 >= 4X + 2 = ok(g(X)) d(ok(X)) = 20X + 10 >= 20X + 2 = ok(d(X)) h(ok(X)) = 20X + 10 >= 20X + 2 = ok(h(X)) top(mark(X)) = 4X + 7 >= 4X + 7 = top(proper(X)) top(ok(X)) = 16X + 15 >= 16X + 7 = top(active(X)) problem: active(f(f(X))) -> mark(c(f(g(f(X))))) active(c(X)) -> mark(d(X)) active(h(X)) -> mark(c(d(X))) active(f(X)) -> f(active(X)) active(h(X)) -> h(active(X)) f(mark(X)) -> mark(f(X)) h(mark(X)) -> mark(h(X)) proper(f(X)) -> f(proper(X)) proper(c(X)) -> c(proper(X))
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