details

property	value
status	complete
benchmark	Ex4_4_Luc96b_FR.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n049.star.cs.uiowa.edu
space	Transformed_CSR_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	3.03114104271 seconds
cpu usage	8.318837602
max memory	5.2850688E8

stage attributes

key	value
output-size	8910
starexec-result	NO

output

/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) QDP (5) QDPOrderProof [EQUIVALENT, 7 ms] (6) QDP (7) QDPOrderProof [EQUIVALENT, 0 ms] (8) QDP (9) TransformationProof [EQUIVALENT, 0 ms] (10) QDP (11) NonTerminationLoopProof [COMPLETE, 0 ms] (12) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(g(X), Y) -> f(X, n__f(n__g(X), activate(Y))) f(X1, X2) -> n__f(X1, X2) g(X) -> n__g(X) activate(n__f(X1, X2)) -> f(activate(X1), X2) activate(n__g(X)) -> g(activate(X)) activate(X) -> X Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: F(g(X), Y) -> F(X, n__f(n__g(X), activate(Y))) F(g(X), Y) -> ACTIVATE(Y) ACTIVATE(n__f(X1, X2)) -> F(activate(X1), X2) ACTIVATE(n__f(X1, X2)) -> ACTIVATE(X1) ACTIVATE(n__g(X)) -> G(activate(X)) ACTIVATE(n__g(X)) -> ACTIVATE(X) The TRS R consists of the following rules: f(g(X), Y) -> f(X, n__f(n__g(X), activate(Y))) f(X1, X2) -> n__f(X1, X2) g(X) -> n__g(X) activate(n__f(X1, X2)) -> f(activate(X1), X2) activate(n__g(X)) -> g(activate(X)) activate(X) -> X Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: F(g(X), Y) -> ACTIVATE(Y) ACTIVATE(n__f(X1, X2)) -> F(activate(X1), X2) F(g(X), Y) -> F(X, n__f(n__g(X), activate(Y))) ACTIVATE(n__f(X1, X2)) -> ACTIVATE(X1) ACTIVATE(n__g(X)) -> ACTIVATE(X) The TRS R consists of the following rules: f(g(X), Y) -> f(X, n__f(n__g(X), activate(Y))) f(X1, X2) -> n__f(X1, X2) g(X) -> n__g(X) activate(n__f(X1, X2)) -> f(activate(X1), X2) activate(n__g(X)) -> g(activate(X)) activate(X) -> X Q is empty. popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Stand 20472