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TRS Stand 20472 pair #381717057
details
property
value
status
complete
benchmark
Ex15_Luc06_iGM.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n047.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.50056099892 seconds
cpu usage
3.349338342
max memory
2.36085248E8
stage attributes
key
value
output-size
2882
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (2) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: active(f(f(a))) -> mark(f(g(f(a)))) mark(f(X)) -> active(f(X)) mark(a) -> active(a) mark(g(X)) -> active(g(mark(X))) f(mark(X)) -> f(X) f(active(X)) -> f(X) g(mark(X)) -> g(X) g(active(X)) -> g(X) Q is empty. ---------------------------------------- (1) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 2. This implies Q-termination of R. The following rules were used to construct the certificate: active(f(f(a))) -> mark(f(g(f(a)))) mark(f(X)) -> active(f(X)) mark(a) -> active(a) mark(g(X)) -> active(g(mark(X))) f(mark(X)) -> f(X) f(active(X)) -> f(X) g(mark(X)) -> g(X) g(active(X)) -> g(X) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 29 Node 1 is start node and node 2 is final node. Those nodes are connected through the following edges: * 1 to 3 labelled mark_1(0)* 1 to 7 labelled active_1(0)* 1 to 6 labelled active_1(0)* 1 to 8 labelled active_1(0)* 1 to 2 labelled f_1(0), g_1(0), f_1(1), g_1(1)* 1 to 10 labelled active_1(1)* 1 to 13 labelled mark_1(1)* 1 to 29 labelled active_1(2)* 2 to 2 labelled #_1(0)* 3 to 4 labelled f_1(0)* 4 to 5 labelled g_1(0)* 5 to 6 labelled f_1(0)* 6 to 2 labelled a(0)* 7 to 2 labelled f_1(0), f_1(1), a(1)* 8 to 9 labelled g_1(0)* 8 to 2 labelled g_1(1)* 8 to 7 labelled g_1(1)* 8 to 11 labelled g_1(1)* 8 to 13 labelled g_1(1)* 8 to 29 labelled g_1(1)* 9 to 2 labelled mark_1(0)* 9 to 7 labelled active_1(1)* 9 to 11 labelled active_1(1)* 9 to 13 labelled mark_1(1)* 9 to 29 labelled active_1(2)* 10 to 4 labelled f_1(1)* 11 to 12 labelled g_1(1)* 11 to 2 labelled g_1(2), g_1(1)* 11 to 7 labelled g_1(2)* 11 to 11 labelled g_1(2)* 11 to 13 labelled g_1(2)* 11 to 29 labelled g_1(2)* 12 to 2 labelled mark_1(1)* 12 to 7 labelled active_1(1)* 12 to 11 labelled active_1(1)* 12 to 13 labelled mark_1(1)* 12 to 29 labelled active_1(2)* 13 to 14 labelled f_1(1)* 14 to 15 labelled g_1(1)* 15 to 16 labelled f_1(1)* 16 to 2 labelled a(1)* 29 to 14 labelled f_1(2) ---------------------------------------- (2) YES
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