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SRS Stand 10685 pair #381717183
details
property
value
status
complete
benchmark
x02.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n089.star.cs.uiowa.edu
space
Secret_07_SRS
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
27.5216939449 seconds
cpu usage
106.943022806
max memory
5.49337088E9
stage attributes
key
value
output-size
56537
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) FlatCCProof [EQUIVALENT, 0 ms] (2) QTRS (3) RootLabelingProof [EQUIVALENT, 7 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 309 ms] (6) QTRS (7) DependencyPairsProof [EQUIVALENT, 82 ms] (8) QDP (9) DependencyGraphProof [EQUIVALENT, 0 ms] (10) QDP (11) QDPOrderProof [EQUIVALENT, 4489 ms] (12) QDP (13) DependencyGraphProof [EQUIVALENT, 0 ms] (14) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(x1)) -> c(d(x1)) d(d(x1)) -> b(e(x1)) b(x1) -> d(c(x1)) d(x1) -> x1 e(c(x1)) -> d(a(x1)) a(x1) -> e(d(x1)) Q is empty. ---------------------------------------- (1) FlatCCProof (EQUIVALENT) We used flat context closure [ROOTLAB] As Q is empty the flat context closure was sound AND complete. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(b(x1))) -> a(c(d(x1))) b(a(b(x1))) -> b(c(d(x1))) c(a(b(x1))) -> c(c(d(x1))) d(a(b(x1))) -> d(c(d(x1))) e(a(b(x1))) -> e(c(d(x1))) a(d(d(x1))) -> a(b(e(x1))) b(d(d(x1))) -> b(b(e(x1))) c(d(d(x1))) -> c(b(e(x1))) d(d(d(x1))) -> d(b(e(x1))) e(d(d(x1))) -> e(b(e(x1))) a(b(x1)) -> a(d(c(x1))) b(b(x1)) -> b(d(c(x1))) c(b(x1)) -> c(d(c(x1))) d(b(x1)) -> d(d(c(x1))) e(b(x1)) -> e(d(c(x1))) a(d(x1)) -> a(x1) b(d(x1)) -> b(x1) c(d(x1)) -> c(x1) d(d(x1)) -> d(x1) e(d(x1)) -> e(x1) a(e(c(x1))) -> a(d(a(x1))) b(e(c(x1))) -> b(d(a(x1))) c(e(c(x1))) -> c(d(a(x1))) d(e(c(x1))) -> d(d(a(x1))) e(e(c(x1))) -> e(d(a(x1))) a(a(x1)) -> a(e(d(x1))) b(a(x1)) -> b(e(d(x1))) c(a(x1)) -> c(e(d(x1))) d(a(x1)) -> d(e(d(x1))) e(a(x1)) -> e(e(d(x1))) Q is empty. ---------------------------------------- (3) RootLabelingProof (EQUIVALENT) We used plain root labeling [ROOTLAB] with the following heuristic: LabelAll: All function symbols get labeled As Q is empty the root labeling was sound AND complete.
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