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SRS Stand 10685 pair #381717345
details
property
value
status
complete
benchmark
12.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n033.star.cs.uiowa.edu
space
Bouchare_06
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
24.5016860962 seconds
cpu usage
96.530960095
max memory
1.376944128E9
stage attributes
key
value
output-size
2554
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) Proof: DP Processor: DPs: b#(a(a(x1))) -> b#(x1) b#(a(a(x1))) -> b#(a(b(x1))) TRS: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) Arctic Interpretation Processor: dimension: 2 usable rules: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) interpretation: [b#](x0) = [0 1]x0, [0 0] [a](x0) = [1 0]x0, [0 0] [b](x0) = [1 1]x0 orientation: b#(a(a(x1))) = [2 2]x1 >= [0 1]x1 = b#(x1) b#(a(a(x1))) = [2 2]x1 >= [2 2]x1 = b#(a(b(x1))) [1 1] [1 1] b(b(x1)) = [2 2]x1 >= [2 1]x1 = a(a(a(x1))) [1 1] [0 0] b(a(b(x1))) = [2 2]x1 >= [1 0]x1 = a(x1) [1 1] [1 1] b(a(a(x1))) = [2 2]x1 >= [2 2]x1 = b(a(b(x1))) problem: DPs: b#(a(a(x1))) -> b#(a(b(x1))) TRS: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) Restore Modifier: DPs: b#(a(a(x1))) -> b#(a(b(x1))) TRS: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) Arctic Interpretation Processor: dimension: 2 usable rules: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) interpretation: [b#](x0) = [-& 1 ]x0 + [0], [-& 1 ] [1] [a](x0) = [1 -&]x0 + [0], [-& 0 ] [0] [b](x0) = [0 3 ]x0 + [3] orientation: b#(a(a(x1))) = [-& 3 ]x1 + [3] >= [-& 2 ]x1 + [2] = b#(a(b(x1))) [0 3] [3] [-& 3 ] [3] b(b(x1)) = [3 6]x1 + [6] >= [3 -&]x1 + [2] = a(a(a(x1))) [-& 1 ] [1] [-& 1 ] [1] b(a(b(x1))) = [1 4 ]x1 + [4] >= [1 -&]x1 + [0] = a(x1) [-& 2 ] [2] [-& 1 ] [1] b(a(a(x1))) = [2 5 ]x1 + [5] >= [1 4 ]x1 + [4] = b(a(b(x1))) problem: DPs: TRS: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) Qed
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