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SRS Stand 10685 pair #381717455
details
property
value
status
complete
benchmark
aprove1.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n025.star.cs.uiowa.edu
space
Secret_05_SRS
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
6.4997420311 seconds
cpu usage
22.569573109
max memory
3.681480704E9
stage attributes
key
value
output-size
17284
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 9 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) AND (5) QDP (6) UsableRulesProof [EQUIVALENT, 0 ms] (7) QDP (8) QDPOrderProof [EQUIVALENT, 0 ms] (9) QDP (10) PisEmptyProof [EQUIVALENT, 0 ms] (11) YES (12) QDP (13) UsableRulesProof [EQUIVALENT, 0 ms] (14) QDP (15) QDPSizeChangeProof [EQUIVALENT, 0 ms] (16) YES (17) QDP (18) UsableRulesProof [EQUIVALENT, 0 ms] (19) QDP (20) MRRProof [EQUIVALENT, 0 ms] (21) QDP (22) MNOCProof [EQUIVALENT, 0 ms] (23) QDP (24) UsableRulesProof [EQUIVALENT, 0 ms] (25) QDP (26) QDPOrderProof [EQUIVALENT, 0 ms] (27) QDP (28) PisEmptyProof [EQUIVALENT, 0 ms] (29) YES (30) QDP (31) UsableRulesProof [EQUIVALENT, 0 ms] (32) QDP (33) MRRProof [EQUIVALENT, 14 ms] (34) QDP (35) MNOCProof [EQUIVALENT, 0 ms] (36) QDP (37) UsableRulesProof [EQUIVALENT, 0 ms] (38) QDP (39) QDPOrderProof [EQUIVALENT, 145 ms] (40) QDP (41) DependencyGraphProof [EQUIVALENT, 0 ms] (42) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: p(0(x1)) -> 0(s(s(p(x1)))) p(s(x1)) -> x1 p(p(s(x1))) -> p(x1) f(s(x1)) -> g(s(x1)) g(x1) -> i(s(half(x1))) i(x1) -> f(p(x1)) half(0(x1)) -> 0(s(s(half(x1)))) half(s(s(x1))) -> s(half(p(p(s(s(x1)))))) 0(x1) -> x1 rd(0(x1)) -> 0(0(0(0(0(0(rd(x1))))))) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: P(0(x1)) -> 0^1(s(s(p(x1)))) P(0(x1)) -> P(x1) P(p(s(x1))) -> P(x1) F(s(x1)) -> G(s(x1)) G(x1) -> I(s(half(x1))) G(x1) -> HALF(x1) I(x1) -> F(p(x1)) I(x1) -> P(x1) HALF(0(x1)) -> 0^1(s(s(half(x1)))) HALF(0(x1)) -> HALF(x1) HALF(s(s(x1))) -> HALF(p(p(s(s(x1)))))
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