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SRS Stand 10685 pair #381717592
details
property
value
status
complete
benchmark
08-oppelt08.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n099.star.cs.uiowa.edu
space
Mixed_SRS
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.58947706223 seconds
cpu usage
6.896803493
max memory
5.74656512E8
stage attributes
key
value
output-size
1494
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 269 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(a(L(x1))) -> L(a(L(X(b(a(b(b(x1)))))))) b(L(x1)) -> L(b(x1)) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "b a (b)^k L a L -> L a L X b a (b)^k+1 L a L X b a b b" b a (b)^k L a L -> L a L X b a (b)^k+1 L a L X b a b b by Overlap u with r (ol3)"b a (b)^k L -> L a L X b a (b)^k+1 b by Operation expand"b a (b)^k L -> L a L X b a (b)^k+2 by Equivalent"b a (b)^k L -> L a L X b a b b (b)^k by Overlap u with l (ol4)"(b)^k L -> L (b)^k by Selfoverlapping OC am1"b L -> L b by original rule (OC 1)"""b a L -> L a L X b a b b by original rule (OC 1)"""""b a L -> L a L X b a b b by original rule (OC 1)" ---------------------------------------- (2) NO
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