details

property	value
status	complete
benchmark	hom02.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n002.star.cs.uiowa.edu
space	Trafo_06

run statistics

property	value
solver	ttt2-1.17+nonreach
configuration	ttt2-1.17+nonreach
runtime (wallclock)	1.6913561821 seconds
cpu usage	5.456086063
max memory	4.9760256E8

stage attributes

key	value
output-size	1616
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(x1) -> b(b(x1)) a(b(b(x1))) -> b(b(c(c(c(a(x1)))))) b(b(x1)) -> c(c(c(x1))) c(c(c(b(b(x1))))) -> a(x1) Proof: String Reversal Processor: a(x1) -> b(b(x1)) b(b(a(x1))) -> a(c(c(c(b(b(x1)))))) b(b(x1)) -> c(c(c(x1))) b(b(c(c(c(x1))))) -> a(x1) Matrix Interpretation Processor: dim=1 interpretation: [c](x0) = x0, [b](x0) = 2x0 + 1, [a](x0) = 4x0 + 3 orientation: a(x1) = 4x1 + 3 >= 4x1 + 3 = b(b(x1)) b(b(a(x1))) = 16x1 + 15 >= 16x1 + 15 = a(c(c(c(b(b(x1)))))) b(b(x1)) = 4x1 + 3 >= x1 = c(c(c(x1))) b(b(c(c(c(x1))))) = 4x1 + 3 >= 4x1 + 3 = a(x1) problem: a(x1) -> b(b(x1)) b(b(a(x1))) -> a(c(c(c(b(b(x1)))))) b(b(c(c(c(x1))))) -> a(x1) Matrix Interpretation Processor: dim=1 interpretation: [c](x0) = x0 + 1, [b](x0) = 2x0, [a](x0) = 4x0 + 4 orientation: a(x1) = 4x1 + 4 >= 4x1 = b(b(x1)) b(b(a(x1))) = 16x1 + 16 >= 16x1 + 16 = a(c(c(c(b(b(x1)))))) b(b(c(c(c(x1))))) = 4x1 + 12 >= 4x1 + 4 = a(x1) problem: b(b(a(x1))) -> a(c(c(c(b(b(x1)))))) String Reversal Processor: a(b(b(x1))) -> b(b(c(c(c(a(x1)))))) KBO Processor: weight function: w0 = 1 w(b) = w(a) = 1 w(c) = 0 precedence: c > a > b problem: Qed popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to SRS Stand 10685