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SRS Stand 10685 pair #381718133
details
property
value
status
complete
benchmark
z084.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n112.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.656174898148 seconds
cpu usage
0.573933518
max memory
6586368.0
stage attributes
key
value
output-size
3596
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x1) (RULES a(x1) -> c(b(x1)) b(b(x1)) -> a(c(x1)) b(c(x1)) -> a(x1) c(c(c(x1))) -> b(x1) ) Problem 1: Dependency Pairs Processor: -> Pairs: A(x1) -> B(x1) A(x1) -> C(b(x1)) B(b(x1)) -> A(c(x1)) B(b(x1)) -> C(x1) B(c(x1)) -> A(x1) C(c(c(x1))) -> B(x1) -> Rules: a(x1) -> c(b(x1)) b(b(x1)) -> a(c(x1)) b(c(x1)) -> a(x1) c(c(c(x1))) -> b(x1) Problem 1: SCC Processor: -> Pairs: A(x1) -> B(x1) A(x1) -> C(b(x1)) B(b(x1)) -> A(c(x1)) B(b(x1)) -> C(x1) B(c(x1)) -> A(x1) C(c(c(x1))) -> B(x1) -> Rules: a(x1) -> c(b(x1)) b(b(x1)) -> a(c(x1)) b(c(x1)) -> a(x1) c(c(c(x1))) -> b(x1) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: A(x1) -> B(x1) A(x1) -> C(b(x1)) B(b(x1)) -> A(c(x1)) B(b(x1)) -> C(x1) B(c(x1)) -> A(x1) C(c(c(x1))) -> B(x1) ->->-> Rules: a(x1) -> c(b(x1)) b(b(x1)) -> a(c(x1)) b(c(x1)) -> a(x1) c(c(c(x1))) -> b(x1) Problem 1: Reduction Pair Processor: -> Pairs: A(x1) -> B(x1) A(x1) -> C(b(x1)) B(b(x1)) -> A(c(x1)) B(b(x1)) -> C(x1) B(c(x1)) -> A(x1) C(c(c(x1))) -> B(x1) -> Rules: a(x1) -> c(b(x1)) b(b(x1)) -> a(c(x1)) b(c(x1)) -> a(x1) c(c(c(x1))) -> b(x1) -> Usable rules: a(x1) -> c(b(x1)) b(b(x1)) -> a(c(x1)) b(c(x1)) -> a(x1) c(c(c(x1))) -> b(x1) ->Interpretation type: Linear ->Coefficients: All rationals ->Dimension: 1 ->Bound: 4 ->Interpretation: [a](X) = X + 2 [b](X) = X + 4/3 [c](X) = X + 2/3 [A](X) = 3.X + 4 [B](X) = 3.X + 3 [C](X) = 3.X
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