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SRS Stand 10685 pair #381718202
details
property
value
status
complete
benchmark
04.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n104.star.cs.uiowa.edu
space
Zantema_06
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.126682043076 seconds
cpu usage
0.110832068
max memory
4030464.0
stage attributes
key
value
output-size
4925
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x1) (RULES a(a(b(x1))) -> b(a(x1)) a(c(x1)) -> c(b(x1)) b(a(a(x1))) -> a(a(a(b(x1)))) ) Problem 1: Dependency Pairs Processor: -> Pairs: A(a(b(x1))) -> A(x1) A(a(b(x1))) -> B(a(x1)) A(c(x1)) -> B(x1) B(a(a(x1))) -> A(a(a(b(x1)))) B(a(a(x1))) -> A(a(b(x1))) B(a(a(x1))) -> A(b(x1)) B(a(a(x1))) -> B(x1) -> Rules: a(a(b(x1))) -> b(a(x1)) a(c(x1)) -> c(b(x1)) b(a(a(x1))) -> a(a(a(b(x1)))) Problem 1: SCC Processor: -> Pairs: A(a(b(x1))) -> A(x1) A(a(b(x1))) -> B(a(x1)) A(c(x1)) -> B(x1) B(a(a(x1))) -> A(a(a(b(x1)))) B(a(a(x1))) -> A(a(b(x1))) B(a(a(x1))) -> A(b(x1)) B(a(a(x1))) -> B(x1) -> Rules: a(a(b(x1))) -> b(a(x1)) a(c(x1)) -> c(b(x1)) b(a(a(x1))) -> a(a(a(b(x1)))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: A(a(b(x1))) -> A(x1) A(a(b(x1))) -> B(a(x1)) A(c(x1)) -> B(x1) B(a(a(x1))) -> A(a(a(b(x1)))) B(a(a(x1))) -> A(a(b(x1))) B(a(a(x1))) -> A(b(x1)) B(a(a(x1))) -> B(x1) ->->-> Rules: a(a(b(x1))) -> b(a(x1)) a(c(x1)) -> c(b(x1)) b(a(a(x1))) -> a(a(a(b(x1)))) Problem 1: Reduction Pair Processor: -> Pairs: A(a(b(x1))) -> A(x1) A(a(b(x1))) -> B(a(x1)) A(c(x1)) -> B(x1) B(a(a(x1))) -> A(a(a(b(x1)))) B(a(a(x1))) -> A(a(b(x1))) B(a(a(x1))) -> A(b(x1)) B(a(a(x1))) -> B(x1) -> Rules: a(a(b(x1))) -> b(a(x1)) a(c(x1)) -> c(b(x1)) b(a(a(x1))) -> a(a(a(b(x1)))) -> Usable rules: a(a(b(x1))) -> b(a(x1)) a(c(x1)) -> c(b(x1)) b(a(a(x1))) -> a(a(a(b(x1)))) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [a](X) = X [b](X) = X [c](X) = X + 2 [A](X) = 2.X + 2 [B](X) = 2.X + 2 Problem 1:
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