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SRS Stand 10685 pair #381718250
details
property
value
status
complete
benchmark
secr10.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n074.star.cs.uiowa.edu
space
Secret_06_SRS
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
25.5589411259 seconds
cpu usage
100.549795508
max memory
1.015037952E9
stage attributes
key
value
output-size
13196
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a(a(x1)) -> c(b(a(b(a(x1))))) b(a(b(x1))) -> b(x1) a(a(a(x1))) -> c(c(a(x1))) c(c(x1)) -> a(b(c(b(a(x1))))) a(c(a(x1))) -> c(c(a(x1))) c(a(c(x1))) -> a(a(c(x1))) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [0] [c](x0) = [0 0 0]x0 + [0] [0 0 0] [1], [1 0 0] [b](x0) = [0 0 0]x0 [0 0 0] , [1 0 1] [0] [a](x0) = [0 0 0]x0 + [0] [0 0 0] [1] orientation: [1 0 1] [1] [1 0 1] [0] a(a(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = c(b(a(b(a(x1))))) [0 0 0] [1] [0 0 0] [1] [1 0 0] [1 0 0] b(a(b(x1))) = [0 0 0]x1 >= [0 0 0]x1 = b(x1) [0 0 0] [0 0 0] [1 0 1] [2] [1 0 1] [2] a(a(a(x1))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = c(c(a(x1))) [0 0 0] [1] [0 0 0] [1] [1 0 1] [1] [1 0 1] [0] c(c(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = a(b(c(b(a(x1))))) [0 0 0] [1] [0 0 0] [1] [1 0 1] [2] [1 0 1] [2] a(c(a(x1))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = c(c(a(x1))) [0 0 0] [1] [0 0 0] [1] [1 0 1] [2] [1 0 1] [2] c(a(c(x1))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = a(a(c(x1))) [0 0 0] [1] [0 0 0] [1] problem: b(a(b(x1))) -> b(x1) a(a(a(x1))) -> c(c(a(x1))) a(c(a(x1))) -> c(c(a(x1))) c(a(c(x1))) -> a(a(c(x1))) Matrix Interpretation Processor: dim=1 interpretation: [c](x0) = x0 + 2, [b](x0) = 4x0, [a](x0) = x0 + 2 orientation: b(a(b(x1))) = 16x1 + 8 >= 4x1 = b(x1) a(a(a(x1))) = x1 + 6 >= x1 + 6 = c(c(a(x1))) a(c(a(x1))) = x1 + 6 >= x1 + 6 = c(c(a(x1))) c(a(c(x1))) = x1 + 6 >= x1 + 6 = a(a(c(x1))) problem: a(a(a(x1))) -> c(c(a(x1))) a(c(a(x1))) -> c(c(a(x1))) c(a(c(x1))) -> a(a(c(x1))) String Reversal Processor: a(a(a(x1))) -> a(c(c(x1))) a(c(a(x1))) -> a(c(c(x1))) c(a(c(x1))) -> c(a(a(x1))) DP Processor: DPs: a#(a(a(x1))) -> c#(x1) a#(a(a(x1))) -> c#(c(x1)) a#(a(a(x1))) -> a#(c(c(x1))) a#(c(a(x1))) -> c#(x1) a#(c(a(x1))) -> c#(c(x1)) a#(c(a(x1))) -> a#(c(c(x1))) c#(a(c(x1))) -> a#(x1) c#(a(c(x1))) -> a#(a(x1)) c#(a(c(x1))) -> c#(a(a(x1))) TRS: a(a(a(x1))) -> a(c(c(x1))) a(c(a(x1))) -> a(c(c(x1))) c(a(c(x1))) -> c(a(a(x1))) TDG Processor:
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