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SRS Stand 10685 pair #381718287
details
property
value
status
complete
benchmark
06-oppelt08.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n191.star.cs.uiowa.edu
space
Mixed_SRS
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.54713106155 seconds
cpu usage
3.501837582
max memory
2.37617152E8
stage attributes
key
value
output-size
1388
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 0 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(c(x1)) -> d(c(x1)) b(d(x1)) -> d(b(x1)) a(d(x1)) -> a(b(b(x1))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a (b)^k d c -> a (b)^k+1 d c" a (b)^k d c -> a (b)^k+1 d c by Overlap u with r (ol3)"a (b)^k d -> a (b)^k+1 b by Operation expand"a (b)^k d -> a (b)^k+2 by Equivalent"a (b)^k d -> a b b (b)^k by Overlap u with l (ol4)"(b)^k d -> d (b)^k by Selfoverlapping OC am1"b d -> d b by original rule (OC 1)"""a d -> a b b by original rule (OC 1)"""""b c -> d c by original rule (OC 1)" ---------------------------------------- (2) NO
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