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SRS Stand 10685 pair #381718387
details
property
value
status
complete
benchmark
e.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n084.star.cs.uiowa.edu
space
Waldmann_06_SRS
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
5.08377313614 seconds
cpu usage
18.855000323
max memory
1.040314368E9
stage attributes
key
value
output-size
12002
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: 2(7(x1)) -> 1(8(x1)) 2(8(1(x1))) -> 8(x1) 2(8(x1)) -> 4(x1) 5(9(x1)) -> 0(x1) 4(x1) -> 5(2(3(x1))) 5(3(x1)) -> 6(0(x1)) 2(8(x1)) -> 7(x1) 4(7(x1)) -> 1(3(x1)) 5(2(6(x1))) -> 6(2(4(x1))) 9(7(x1)) -> 7(5(x1)) 7(2(x1)) -> 4(x1) 7(0(x1)) -> 9(3(x1)) 6(9(x1)) -> 9(x1) 9(5(9(x1))) -> 5(7(x1)) 4(x1) -> 9(6(6(x1))) 9(x1) -> 6(7(x1)) 6(2(x1)) -> 7(7(x1)) 2(4(x1)) -> 0(7(x1)) 6(6(x1)) -> 3(x1) 0(3(x1)) -> 5(3(x1)) Proof: String Reversal Processor: 7(2(x1)) -> 8(1(x1)) 1(8(2(x1))) -> 8(x1) 8(2(x1)) -> 4(x1) 9(5(x1)) -> 0(x1) 4(x1) -> 3(2(5(x1))) 3(5(x1)) -> 0(6(x1)) 8(2(x1)) -> 7(x1) 7(4(x1)) -> 3(1(x1)) 6(2(5(x1))) -> 4(2(6(x1))) 7(9(x1)) -> 5(7(x1)) 2(7(x1)) -> 4(x1) 0(7(x1)) -> 3(9(x1)) 9(6(x1)) -> 9(x1) 9(5(9(x1))) -> 7(5(x1)) 4(x1) -> 6(6(9(x1))) 9(x1) -> 7(6(x1)) 2(6(x1)) -> 7(7(x1)) 4(2(x1)) -> 7(0(x1)) 6(6(x1)) -> 3(x1) 3(0(x1)) -> 3(5(x1)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [6](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [3](x0) = [0 0 0]x0 [0 0 0] , [1 0 1] [0](x0) = [0 0 0]x0 [0 0 0] , [1 0 1] [5](x0) = [0 1 0]x0 [0 0 0] , [1 0 1] [0] [9](x0) = [0 0 0]x0 + [1] [0 0 0] [0], [1 0 1] [4](x0) = [0 0 0]x0 [0 0 0] , [1 0 1] [1](x0) = [0 0 0]x0 [0 0 0] , [1 1 1] [8](x0) = [0 0 0]x0 [0 0 0] , [0] [2](x0) = x0 + [0] [1], [1 0 1] [7](x0) = [0 0 0]x0 [0 0 0] orientation: [1 0 1] [1] [1 0 1] 7(2(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 = 8(1(x1)) [0 0 0] [0] [0 0 0] [1 1 1] [1] [1 1 1]
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